Question: If a three digit positive integer is a multiple of 7, what is the probability that it will be a multiple of 5?
- 1/7
- 1/5
- 11/54
- 13/64
- 13/66
Approach Solution (1)
Number of multiples of 7: 999/7 – 100/7 = 142 – 14 = 128
Number of multiples of 35: 999/35 – 100/35 = 28 – 2 = 26
Probability that a multiple of 7 will be a multiple of 5 = 26/128=13/64
Correct option: D
Approach Solution (2)
3-digit positive integer is a multiple of 7: 105, 112, 119,..., 994.
Calculating 994 = 105 + (n-1)x7, we know that 994 is the 128th (=n) element of the series.
3-digit positive integer that is a multiple of 5 and 7: 105, 140, 175,..., 980.
Calculating 980 = 105 + (n-1)x35, we know that 980 is the 26th (=n) element of the series.
Thus, the probability that it will be both multiple of 5 and 7 is 26/128=13/64
Correct option: D
Approach Solution (3)
So 100 < 7k < 999 (k is an integer)
14 < k < 142
k = 142 - 14 = 128
To find whether these numbers are a multiple of 5, we need to check for LCM (5,7) = 35 multiplicity.
Also, 100 < 35k' < 999 (k' is an integer)
2 < k' < 28
k' = 28 - 2 = 26
Probability = 26/128=13/64
Correct option: D
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