VITEEE PYQs for Magnetic Force with Solutions: Practice VITEEE Previous Year Questions

Updated 3+ months ago

Magnetic Force is an important topic in the Physics section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.

This article gives you a full set of VITEEE PYQs for Magnetic Force with explanations for effective preparation. Practice of VITEEE Physics PYQs including Magnetic Force questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.

VITEEE PYQs for Magnetic Force with Solutions

1.
An electron of mass $9.0 \times 10^{-31} kg$ under the action of a magnetic field moves in a circle of radius $2\, cm$ at a speed of $3 \times 10^6 \, m/s$ . If a proton of mass $1.8 \times 10^{27} \, kg$ was to move in a circle of same radius in the same magnetic field, then its speed will become
- $1.5 \times 10^3 \, m/s$
- $ 3 \times 10^6 \, m/s$
- $6 \times 10^4 \, m/s$
- $2 \times 10^6 \, m/s$
View Solution
2.
A rectangular loop carrying a current $i$ is placed in a uniform magnetic field $B$. The area enclosed by the loop is $A$. If there are $n$ turns in the loop, the torque acting on the loop is given by
- $ni\, A ? B$
- $ni\, A \cdot B$
- $\frac{1}{n}\left(iA\times B\right)$
- $\frac{1}{n}\left(iA\cdot B\right)$
View Solution
3.
In the presence of magnetic field ?B? and electric field ?E?, the total force on a moving charged particle is
- $\vec{F}=\vec{V}[(\vec{q}?\vec{B})+\vec{E}]$
- $\vec{F}=q[(\vec{v}?\vec{E})+\vec{B}]$
- $\vec{F}=q[(\vec{v}?\vec{B})+\vec{E}]$
- $\vec{F}=B[(\vec{q}?\vec{E})+\vec{V}]$
View Solution
4.
An electron of mass $ 9.0 \times 10^{-31} $ kg under the action of a magnetic field moves in a circle of radius 2 cm at a speed of $ 3 \times 10^6 $ m/s. A proton of mass $ 1.8 \times 10^{-27} $ kg moves in a circle of same radius in the same magnetic field, then its speed will become
- $ 1.5 \times 10^3 \, \text{m/s} $
- $ 3 \times 10^6 \, \text{m/s} $
- $ 6 \times 10^4 \, \text{m/s} $
- $ 1.0 \times 10^5 \, \text{m/s} $
View Solution

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VITEEE PYQs for Magnetic Force with Solutions

2.A rectangular loop carrying a current $i$ is placed in a uniform magnetic field $B$. The area enclosed by the loop is $A$. If there are $n$ turns in the loop, the torque acting on the loop is given by

3.In the presence of magnetic field ?B? and electric field ?E?, the total force on a moving charged particle is

4.An electron of mass \( 9.0 \times 10^{-31} \) kg under the action of a magnetic field moves in a circle of radius 2 cm at a speed of \( 3 \times 10^6 \) m/s. A proton of mass \( 1.8 \times 10^{-27} \) kg moves in a circle of same radius in the same magnetic field, then its speed will become

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2.
A rectangular loop carrying a current $i$ is placed in a uniform magnetic field $B$. The area enclosed by the loop is $A$. If there are $n$ turns in the loop, the torque acting on the loop is given by

3.
In the presence of magnetic field ?B? and electric field ?E?, the total force on a moving charged particle is

4.
An electron of mass \( 9.0 \times 10^{-31} \) kg under the action of a magnetic field moves in a circle of radius 2 cm at a speed of \( 3 \times 10^6 \) m/s. A proton of mass \( 1.8 \times 10^{-27} \) kg moves in a circle of same radius in the same magnetic field, then its speed will become