VITEEE PYQs for Rate of a Chemical Reaction with Solutions: Practice VITEEE Previous Year Questions

Updated 3+ months ago

Rate of a Chemical Reaction is an important topic in the Chemistry section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.

This article gives you a full set of VITEEE PYQs for Rate of a Chemical Reaction with explanations for effective preparation. Practice of VITEEE Chemistry PYQs including Rate of a Chemical Reaction questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.

VITEEE PYQs for Rate of a Chemical Reaction with Solutions

1.
For the reaction $2N_2O_5 \to 4NO_2 + O_2$, rate and rate constant are $1.02 \times 10^{-4}$ mol $lir^{-1}$ $sec^{-1}$ and $3.4 \times 10^{-5}$ $sec^{-1}$ respectively then concentration of $N_2O_5$ at that time will be
- 1.732 M
- 3 M
- $3.4\times 10^{-5}M$
- $1.02 \times 10^{-4}M$
View Solution
2.
In the reversible reaction, $2 NO _{2} \ce{->[{k_{1}}][{K_{2}}]} N _{2} O _{4}$ the rate of disappearance of $N O_{2}$ is equal to
- $\frac{2k_{1}}{k_{2}}\left[NO_{2}\right]^{2}$
- $2k_{1}\left[NO_{2}\right]^{2} - 2k_{2}\left[N_{2}O_{4}\right]$
- $2k_{1}\left[NO_{2}\right]^{2} - k_{2}\left[N_{2}O_{4}\right]$
- $\left(2k_{1} - k_{2}\right) \left[NO_{2}\right]$
View Solution
3.
For the reaction $N_{2}+3H_{2} \rightarrow 2NH_{3}$ if $\frac{\Delta\left[NH_{3}\right]}{\Delta t}=2\times10^{-4}\,mol\,l^{-1}s^{-1},$ then value of $\frac{-\Delta\left[H_{2}\right]}{\Delta t}$ would be
- $1 � 10^{-4}\, mol\, L^{-1}s^{-1}$
- $3 � 10^{-4}\, mol\, L^{-1}s^{-1}$
- $4 � 10^{-4}\, mol\, L^{-1}s^{-1}$
- $6 � 10^{-4}\, mol\, L^{-1}s^{-1}$
View Solution
4.
A gaseous reaction $X_2(g) \to Y + \frac{1}{2} Z(g)$ There is increase in pressure from $100 \,mm$ to $120 \,mm$ in $5$ minutes. The rate of disappearance of $X_2$ is
- $8 \,mm \min ^{-1}$
- $2\, mm \min ^{-1}$
- $16\, mm \min ^{-1}$
- $4\, mm \min ^{-1}$
View Solution

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VITEEE PYQs for Rate of a Chemical Reaction with Solutions

1.For the reaction $2N_2O_5 \to 4NO_2 + O_2$, rate and rate constant are $1.02 \times 10^{-4}$ mol $lir^{-1}$ $sec^{-1}$ and $3.4 \times 10^{-5}$ $sec^{-1}$ respectively then concentration of $N_2O_5$ at that time will be

2.In the reversible reaction, $2 NO _{2} \ce{->[{k_{1}}][{K_{2}}]} N _{2} O _{4}$ the rate of disappearance of $N O_{2}$ is equal to

3.For the reaction $N_{2}+3H_{2} \rightarrow 2NH_{3}$ if $\frac{\Delta\left[NH_{3}\right]}{\Delta t}=2\times10^{-4}\,mol\,l^{-1}s^{-1},$ then value of $\frac{-\Delta\left[H_{2}\right]}{\Delta t}$ would be

4.A gaseous reaction $X_2(g) \to Y + \frac{1}{2} Z(g)$ There is increase in pressure from $100 \,mm$ to $120 \,mm$ in $5$ minutes. The rate of disappearance of $X_2$ is

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1.
For the reaction $2N_2O_5 \to 4NO_2 + O_2$, rate and rate constant are $1.02 \times 10^{-4}$ mol $lir^{-1}$ $sec^{-1}$ and $3.4 \times 10^{-5}$ $sec^{-1}$ respectively then concentration of $N_2O_5$ at that time will be

2.
In the reversible reaction, $2 NO _{2} \ce{->[{k_{1}}][{K_{2}}]} N _{2} O _{4}$ the rate of disappearance of $N O_{2}$ is equal to

3.
For the reaction $N_{2}+3H_{2} \rightarrow 2NH_{3}$ if $\frac{\Delta\left[NH_{3}\right]}{\Delta t}=2\times10^{-4}\,mol\,l^{-1}s^{-1},$ then value of $\frac{-\Delta\left[H_{2}\right]}{\Delta t}$ would be

4.
A gaseous reaction $X_2(g) \to Y + \frac{1}{2} Z(g)$ There is increase in pressure from $100 \,mm$ to $120 \,mm$ in $5$ minutes. The rate of disappearance of $X_2$ is