VITEEE PYQs for sets with Solutions: Practice VITEEE Previous Year Questions

Updated 3+ months ago

sets is an important topic in the Mathematics section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.

This article gives you a full set of VITEEE PYQs for sets with explanations for effective preparation. Practice of VITEEE Mathematics PYQs including sets questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.

VITEEE PYQs for sets with Solutions

1.
Let $ R $ be a relation on the set $ \mathbb{N} $ defined by \[ \{(x, y) \mid x, y \in \mathbb{N}, \, 2x + y = 41\}. \] {Then, $ R $ is:}
- Reflexive
- Symmetric
- Transitive
- None of these
View Solution
2.
The function $ f : \mathbb{R} \to \mathbb{R} $ defined by $ f(x) = x^2 + x $ is:
- One-one
- Onto
- Many-one
- None of these
View Solution
3.
The lines $$ p(p^2 + 1)x - y + q = 0 \quad {and} \quad (p^2 + 1)^2 x + (p^2 + 1)y + 2q = 0 $$ are perpendicular to a common line for:
- Exactly one value of $ p $
- Exactly two values of $ p $
- More than two values of $ p $
- No value of $ p $
View Solution
4.
The probability that a card drawn from a pack of 52 cards will be a diamond or a king is:
- $ \frac{1}{52} $
- $ \frac{2}{13} $
- $ \frac{4}{13} $
- $ \frac{1}{13} $
View Solution
5.
A class has 175 students. The following data shows the number of students opting for one or more subjects. Maths = 100, Physics = 70, Chemistry = 40, Maths and Physics = 30, Maths and Chemistry = 28, Physics and Chemistry = 23, Maths, Physics, and Chemistry = 18.
How many have offered Maths alone?
- 35
- 48
- 60
- 22
View Solution
6.
The argument of the complex number \[ \left( \frac{i}{2} - \frac{2}{i} \right) \] is equal to:
- $ \frac{\pi}{4} $
- $ \frac{3\pi}{4} $
- $ \frac{\pi}{12} $
- $ \frac{\pi}{2} $
View Solution

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VITEEE PYQs for sets with Solutions: Practice VITEEE Previous Year Questions

VITEEE PYQs for sets with Solutions

1.
Let \( R \) be a relation on the set \( \mathbb{N} \) defined by \[ \{(x, y) \mid x, y \in \mathbb{N}, \, 2x + y = 41\}. \] {Then, \( R \) is:}

2.
The function \( f : \mathbb{R} \to \mathbb{R} \) defined by \( f(x) = x^2 + x \) is:

3.
The lines $$ p(p^2 + 1)x - y + q = 0 \quad {and} \quad (p^2 + 1)^2 x + (p^2 + 1)y + 2q = 0 $$ are perpendicular to a common line for:

4.
The probability that a card drawn from a pack of 52 cards will be a diamond or a king is:

6.
The argument of the complex number \[ \left( \frac{i}{2} - \frac{2}{i} \right) \] is equal to:

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VITEEE PYQs for sets with Solutions

1.Let \( R \) be a relation on the set \( \mathbb{N} \) defined by \[ \{(x, y) \mid x, y \in \mathbb{N}, \, 2x + y = 41\}. \] {Then, \( R \) is:}

2.The function \( f : \mathbb{R} \to \mathbb{R} \) defined by \( f(x) = x^2 + x \) is:

3.The lines $$ p(p^2 + 1)x - y + q = 0 \quad {and} \quad (p^2 + 1)^2 x + (p^2 + 1)y + 2q = 0 $$ are perpendicular to a common line for:

4.The probability that a card drawn from a pack of 52 cards will be a diamond or a king is:

6.The argument of the complex number \[ \left( \frac{i}{2} - \frac{2}{i} \right) \] is equal to:

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1.
Let \( R \) be a relation on the set \( \mathbb{N} \) defined by \[ \{(x, y) \mid x, y \in \mathbb{N}, \, 2x + y = 41\}. \] {Then, \( R \) is:}

2.
The function \( f : \mathbb{R} \to \mathbb{R} \) defined by \( f(x) = x^2 + x \) is:

3.
The lines $$ p(p^2 + 1)x - y + q = 0 \quad {and} \quad (p^2 + 1)^2 x + (p^2 + 1)y + 2q = 0 $$ are perpendicular to a common line for:

4.
The probability that a card drawn from a pack of 52 cards will be a diamond or a king is:

6.
The argument of the complex number \[ \left( \frac{i}{2} - \frac{2}{i} \right) \] is equal to: