NCERT Solutions for Class 10 Maths Chapter 4 Exercise 4.3

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NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.3 is given in this article with step by step explanation. Class 10 Maths Chapter 4 Exercise 4.3 has eleven questions on the different ways to calculate the unknown values of x.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 4 Quadratic Equations 4.3

Check out other exercise solutions of Class 10 Maths Chapter 4

Class 10 Chapter 4 Topics:

Arithmetic Sequence Formula	Fundamental Theorem of Arithmetic	Arithmetic Progression Formula
Nature of Roots	Discriminant Formula	Quadratic Interpolation Formula
Quadratic Equations Formula	Quadratic Equations MCQ	Complex Numbers and Quadratic Equations

CBSE Class 10 Maths Study Guides:

Calculus	Mensuration	Arithmetic
Difference between in Maths	NCERT Solutions for Class 10 Maths	Math MCQs
Geometry	Number System	Class 10 Notes
Trigonometry	Math Study Notes	Math Formula

CBSE X Related Questions

1.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
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2.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
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3.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
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4.
For any natural number n, \( 5^n \) ends with the digit :
- 0
- 5
- 3
- 2
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5.
Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.
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6.
A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))
- \(314 \sqrt{2}\) \(\text{cm}^{2}\)
- \(314\) \(\text{cm}^{2}\)
- \(\frac{3140}{3}\) \(\text{cm}^{2}\)
- \(3140 \sqrt{2}\) \(\text{cm}^{2}\)
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