BITSAT 2025 Question Paper June 25 Shift 2 (Available): Download Solutions with Answer Key

The BITSAT 2025 Exam was conducted on June 25^th 2025 Shift 2 from 2:00 P.M. to 5:00 P.M. in a CBT Mode at various exam centres in India.

The exam tests candidates based on their speed, accuracy, and ability to apply concepts. It consists of 130 multiple-choice questions covering subjects like Physics, Chemistry, English Proficiency, Logical Reasoning, and Mathematics/Biology.

BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT 2025 Question Paper with Answer Key June 25 Shift 2
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Question 1:

A car accelerates from rest to a speed of 20 m/s in 10 seconds. What is its acceleration?

(1) 2 m/s²
(2) 3 m/s²
(3) 4 m/s²
(4) 5 m/s²

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Question 2:

Which of the following is the correct unit for electric charge?

(1) Coulomb
(2) Ampere
(3) Volt
(4) Joule

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Question 3:

Which of the following has the greatest electronegativity?

(1) Fluorine
(2) Oxygen
(3) Nitrogen
(4) Chlorine

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Question 4:

What is the value of $ \sin 30^\circ $?

(1) $ \frac{1}{2} $
(2) $ \frac{\sqrt{3}}{2} $
(3) $ 1 $
(4) $ 0 $

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Question 5:

The number of significant figures in the measurement 0.00456 is:

(1) 2
(2) 3
(3) 4
(4) 5

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Question 6:

Which of the following is the correct electronic configuration for $ Oxygen (O) $?

(1) $ 1s^2 2s^2 2p^4 $
(2) $ 1s^2 2s^2 2p^6 $
(3) $ 1s^2 2s^2 2p^3 $
(4) $ 1s^2 2s^2 3p^2 $

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Question 7:

Which of the following is an example of a scalar quantity?

(1) Velocity
(2) Force
(3) Temperature
(4) Displacement

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Question 8:

The equation of a straight line is given by $ y = 3x + 4 $. What is the slope of the line?

(1) 3
(2) 4
(3) 1
(4) 0

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Question 9:

Which of the following is a non-metal?

(1) Sodium
(2) Iron
(3) Carbon
(4) Copper

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Question 10:

The roots of the equation $ x^2 + 5x + 6 = 0 $ are:

(1) $ -2 $ and $ -3 $
(2) $ 1 $ and $ 6 $
(3) $ -1 $ and $ -6 $
(4) $ -3 $ and $ -2 $

View Solution

BITSAT Topper Strategy on How to Score Good in BITSAT

BITSAT 2025 Expected Marks Vs Rank

With an understanding of the expected marks vs rank, candidates can analyse their performance in BITSAT and estimate their chances of securing admission into different BITS campuses.

Since the BITSAT exam is conducted in multiple shifts, therefore ranks are normalised across sessions.

BITSAT Expected Marks Vs Rank

BITSAT Score Range	Expected Rank Range
380 – 400+	Top 1 – 200
350 – 379	201 – 800
320 – 349	801 – 2,000
290 – 319	2,001 – 4,500
260 – 289	4,501 – 8,000
230 – 259	8,001 – 13,000
200 – 229	13,001 – 20,000
170 – 199	20,001 – 30,000
140 – 169	30,001 – 45,000
Below 140	45,001 and above

BITSAT Questions

1.
A block of mass $ m $ is placed on a smooth inclined wedge ABC of inclination $ \theta $ as shown in the figure. The wedge is given an acceleration $ a $ towards the right. The relation between $ a $ and $ g $ for the block to remain stationary on the wedge is

$ a = \frac{g}{\sec \theta} $
$ a = \frac{g}{\sin \theta} $
$ a = g \tan \theta $
$ a = g \cos \theta $

View Solution

2.
The dimensional formula of latent heat is:

$ [M^0 L T^{-2}] $
$ [M L T^{-2}] $
$ [M^0 L^2 T^{-2}] $
$ [M L^2 T^{-2}] $

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3.
Three blocks of masses m₁, m₂, and m₃ are connected by massless strings on a frictionless table and pulled by a force T₃ = 40 N. If m₁ = 10 kg, m₂ = 6 kg, and m₃ = 4 kg, the tension T₂ will be:

20 N
40 N
10 N
32 N

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4.
Vertical displacement of a plank with a body of mass $m$ on it is varying according to law \[ y=\sin(\omega t)+\sqrt{3}\cos(\omega t). \] The minimum value of $\omega$ for which the mass just breaks off from the plank and the moment it occurs is first after $t=0$, are given by:

$\sqrt{\frac{g}{2}},\;\frac{\sqrt{2}\pi}{6}$
$\sqrt{\frac{g}{3}},\;\frac{2\pi}{\sqrt{3}g}$
$\sqrt{\frac{g}{2}},\;\frac{\pi}{3\sqrt{2}}$
$\sqrt{2g},\;\frac{\sqrt{2}\pi}{3g}$

View Solution

5.
For the reaction $H _{2}( g )+ Br _{2}( g ) \rightarrow 2 HBr ( g )$, the experiment data suggested that $r = k \left[ H _{2}\right]\left[ Br _{2}\right]^{1 / 2} .$ The molecularity and order of the reaction are respectively:

$2, \frac{3}{2}$
$\frac{3}{2}, \frac{3}{2}$
1,1
$1, \frac{1}{2}$

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6.
The linear momentum $p$ of a body moving in one dimension varies with time $t$ according to the equation $p = a + bt^2$, where $a$ and $b$ are positive constant. The net force acting on the body is

a constant
proportional to $t^2$
inversely proportional to $t$
proportional to $t$

View Solution

BITSAT 2025 Question Paper June 25 Shift 2 (Available): Download Solutions with Answer Key

BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT Topper Strategy on How to Score Good in BITSAT

BITSAT 2025 Expected Marks Vs Rank

BITSAT Questions

1.
A block of mass \( m \) is placed on a smooth inclined wedge ABC of inclination \( \theta \) as shown in the figure. The wedge is given an acceleration \( a \) towards the right. The relation between \( a \) and \( g \) for the block to remain stationary on the wedge is

2.
The dimensional formula of latent heat is:

3.
Three blocks of masses m₁, m₂, and m₃ are connected by massless strings on a frictionless table and pulled by a force T₃ = 40 N. If m₁ = 10 kg, m₂ = 6 kg, and m₃ = 4 kg, the tension T₂ will be:

4.
Vertical displacement of a plank with a body of mass \(m\) on it is varying according to law \[ y=\sin(\omega t)+\sqrt{3}\cos(\omega t). \] The minimum value of \(\omega\) for which the mass just breaks off from the plank and the moment it occurs is first after \(t=0\), are given by:

5.
For the reaction $H _{2}( g )+ Br _{2}( g ) \rightarrow 2 HBr ( g )$, the experiment data suggested that $r = k \left[ H _{2}\right]\left[ Br _{2}\right]^{1 / 2} .$ The molecularity and order of the reaction are respectively:

6.
The linear momentum $p$ of a body moving in one dimension varies with time $t$ according to the equation $p = a + bt^2$, where $a$ and $b$ are positive constant. The net force acting on the body is

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BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT Topper Strategy on How to Score Good in BITSAT

BITSAT 2025 Expected Marks Vs Rank

BITSAT Questions

1.A block of mass \( m \) is placed on a smooth inclined wedge ABC of inclination \( \theta \) as shown in the figure. The wedge is given an acceleration \( a \) towards the right. The relation between \( a \) and \( g \) for the block to remain stationary on the wedge is

2.The dimensional formula of latent heat is:

3.Three blocks of masses m₁, m₂, and m₃ are connected by massless strings on a frictionless table and pulled by a force T₃ = 40 N. If m₁ = 10 kg, m₂ = 6 kg, and m₃ = 4 kg, the tension T₂ will be:

4.Vertical displacement of a plank with a body of mass \(m\) on it is varying according to law \[ y=\sin(\omega t)+\sqrt{3}\cos(\omega t). \] The minimum value of \(\omega\) for which the mass just breaks off from the plank and the moment it occurs is first after \(t=0\), are given by:

5.For the reaction $H _{2}( g )+ Br _{2}( g ) \rightarrow 2 HBr ( g )$, the experiment data suggested that $r = k \left[ H _{2}\right]\left[ Br _{2}\right]^{1 / 2} .$ The molecularity and order of the reaction are respectively:

6.The linear momentum $p$ of a body moving in one dimension varies with time $t$ according to the equation $p = a + bt^2$, where $a$ and $b$ are positive constant. The net force acting on the body is

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1.
A block of mass \( m \) is placed on a smooth inclined wedge ABC of inclination \( \theta \) as shown in the figure. The wedge is given an acceleration \( a \) towards the right. The relation between \( a \) and \( g \) for the block to remain stationary on the wedge is

2.
The dimensional formula of latent heat is:

3.
Three blocks of masses m₁, m₂, and m₃ are connected by massless strings on a frictionless table and pulled by a force T₃ = 40 N. If m₁ = 10 kg, m₂ = 6 kg, and m₃ = 4 kg, the tension T₂ will be:

4.
Vertical displacement of a plank with a body of mass \(m\) on it is varying according to law \[ y=\sin(\omega t)+\sqrt{3}\cos(\omega t). \] The minimum value of \(\omega\) for which the mass just breaks off from the plank and the moment it occurs is first after \(t=0\), are given by:

5.
For the reaction $H _{2}( g )+ Br _{2}( g ) \rightarrow 2 HBr ( g )$, the experiment data suggested that $r = k \left[ H _{2}\right]\left[ Br _{2}\right]^{1 / 2} .$ The molecularity and order of the reaction are respectively:

6.
The linear momentum $p$ of a body moving in one dimension varies with time $t$ according to the equation $p = a + bt^2$, where $a$ and $b$ are positive constant. The net force acting on the body is