BITSAT PYQs for Coordinates of a Point in Space with Solutions: Practice BITSAT Previous Year Questions

Updated 3+ months ago

Coordinates of a Point in Space is an important topic in the Mathematics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.

This article gives you a full set of BITSAT PYQs for Coordinates of a Point in Space with explanations for effective preparation. Practice of BITSAT Mathematics PYQs including Coordinates of a Point in Space questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.

BITSAT PYQs for Coordinates of a Point in Space with Solutions

1.
Given \[ \frac{dy}{dx} \tan x = y \sec^2 x + \sin x, \quad {find the general solution:} \]
- $ y = \tan x \left( \log | \csc x - \cot x | + \cos x + c \right) $
- $ y = \sec^2 x + \tan x + c $
- $ y = \log | \sec x + \tan x | + \csc x + c $
- $ y = \tan^2 x + \sin x + c $
View Solution
2.
The area of the region bounded by the parabola $ (y - 2)^2 = (x - 1) $, the tangent to the parabola at the point $ (2, 3) $, and the X-axis is:
- 3
- 6
- 9
- 12
View Solution
3.
The image of the point $(3, 2, 1)$ in the plane $2x-y+3z = 7$ is
- (1, 2, 3)
- (2, 3, 1)
- (3, 2, 1)
- (2, 1, 3)
View Solution
4.
For each parabola $ y = x^2 + px + q $, meeting the coordinate axes at three distinct points, if circles are drawn through these points, then the family of circles must pass through:
- $ (1, 0) $
- $ (0, 1) $
- $ (1, 1) $
- $ (p, q) $
View Solution
5.
If $ |w| = 2 $, then the set of points $ z = w - \frac{1}{w} $ is contained in or equal to the set of points $ z $ satisfying:
- $ {Im}(z) = 0 $
- $ |{Im}(z)| \leq 1 $
- $ |{Re}(z)| \leq 2 $
- $ |z| \leq 3 $
View Solution
6.
If \[ \left[ \begin{array}{cc} 1 & -\tan(\theta) \\ \tan(\theta) & 1 \end{array} \right] \left[ \begin{array}{cc} 1 & \tan(\theta) \\ -\tan(\theta) & 1 \end{array} \right]^{-1} = \left[ \begin{array}{cc} a & -b \\ b & a \end{array} \right], \] then:
- $a = 1, b = 1 $
- $a = \sin 2\theta, b = \cos 2\theta $
- $a = \cos 2\theta, b = \sin 2\theta $
- None of these
View Solution

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BITSAT PYQs for Coordinates of a Point in Space with Solutions: Practice BITSAT Previous Year Questions

BITSAT PYQs for Coordinates of a Point in Space with Solutions

1.
Given \[ \frac{dy}{dx} \tan x = y \sec^2 x + \sin x, \quad {find the general solution:} \]

2.
The area of the region bounded by the parabola \( (y - 2)^2 = (x - 1) \), the tangent to the parabola at the point \( (2, 3) \), and the X-axis is:

3.
The image of the point $(3, 2, 1)$ in the plane $2x-y+3z = 7$ is

4.
For each parabola \( y = x^2 + px + q \), meeting the coordinate axes at three distinct points, if circles are drawn through these points, then the family of circles must pass through:

5.
If \( |w| = 2 \), then the set of points \( z = w - \frac{1}{w} \) is contained in or equal to the set of points \( z \) satisfying:

6.
If \[ \left[ \begin{array}{cc} 1 & -\tan(\theta) \\ \tan(\theta) & 1 \end{array} \right] \left[ \begin{array}{cc} 1 & \tan(\theta) \\ -\tan(\theta) & 1 \end{array} \right]^{-1} = \left[ \begin{array}{cc} a & -b \\ b & a \end{array} \right], \] then:

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BITSAT PYQs for Coordinates of a Point in Space with Solutions

1.Given \[ \frac{dy}{dx} \tan x = y \sec^2 x + \sin x, \quad {find the general solution:} \]

2.The area of the region bounded by the parabola \( (y - 2)^2 = (x - 1) \), the tangent to the parabola at the point \( (2, 3) \), and the X-axis is:

3.The image of the point $(3, 2, 1)$ in the plane $2x-y+3z = 7$ is

4.For each parabola \( y = x^2 + px + q \), meeting the coordinate axes at three distinct points, if circles are drawn through these points, then the family of circles must pass through:

5.If \( |w| = 2 \), then the set of points \( z = w - \frac{1}{w} \) is contained in or equal to the set of points \( z \) satisfying:

6. If \[ \left[ \begin{array}{cc} 1 & -\tan(\theta) \\ \tan(\theta) & 1 \end{array} \right] \left[ \begin{array}{cc} 1 & \tan(\theta) \\ -\tan(\theta) & 1 \end{array} \right]^{-1} = \left[ \begin{array}{cc} a & -b \\ b & a \end{array} \right], \] then:

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1.
Given \[ \frac{dy}{dx} \tan x = y \sec^2 x + \sin x, \quad {find the general solution:} \]

2.
The area of the region bounded by the parabola \( (y - 2)^2 = (x - 1) \), the tangent to the parabola at the point \( (2, 3) \), and the X-axis is:

3.
The image of the point $(3, 2, 1)$ in the plane $2x-y+3z = 7$ is

4.
For each parabola \( y = x^2 + px + q \), meeting the coordinate axes at three distinct points, if circles are drawn through these points, then the family of circles must pass through:

5.
If \( |w| = 2 \), then the set of points \( z = w - \frac{1}{w} \) is contained in or equal to the set of points \( z \) satisfying:

6.
If \[ \left[ \begin{array}{cc} 1 & -\tan(\theta) \\ \tan(\theta) & 1 \end{array} \right] \left[ \begin{array}{cc} 1 & \tan(\theta) \\ -\tan(\theta) & 1 \end{array} \right]^{-1} = \left[ \begin{array}{cc} a & -b \\ b & a \end{array} \right], \] then: