BITSAT PYQs for Distance of a Point From a Line with Solutions: Practice BITSAT Previous Year Questions

Updated 3+ months ago

Distance of a Point From a Line is an important topic in the Mathematics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.

This article gives you a full set of BITSAT PYQs for Distance of a Point From a Line with explanations for effective preparation. Practice of BITSAT Mathematics PYQs including Distance of a Point From a Line questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.

BITSAT PYQs for Distance of a Point From a Line with Solutions

1.
If a point $ P(x, y) $ satisfies the condition that its distance from the point $ (3, -2) $ is equal to its distance from the line $ y = 2x + 1 $, then the locus of point $ P $ is:
- A parabola
- A circle
- A straight line
- A pair of straight lines
View Solution
2.
The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line $$ 4x - 5y = 20 $$ to the circle $$ x^2 + y^2 = 9 \text{ is:} $$
- $ 20(x^2 + y^2) - 36x + 45y = 0 $
- $ 20(x^2 + y^2) + 36x - 45y = 0 $
- $ 36(x^2 + y^2) - 20x + 45y = 0 $
- $ 36(x^2 + y^2) + 20x - 45y = 0 $
View Solution
3.
A normal is drawn at the point $ P $ to the parabola $ y^2 = 8x $, which is inclined at $ 60^\circ $ with the straight line $ y = 8 $. Then the point $ P $ lies on the straight line:
- $ 2x + y - 12 - 4\sqrt{3} = 0 $
- $ 2x - y - 12 + 4\sqrt{3} = 0 $
- $ 2x - y - 12 - 4\sqrt{3} = 0 $
- None of these
View Solution
4.
The nearest point on the line $3x + 4y = 12$ from the origin is
- $\left(\frac{36}{25} , \frac{48}{25}\right) $
- $\left(3 , \frac{3}{4}\right) $
- $\left(2 , \frac{3}{2}\right) $
- None of these
View Solution

View more BITSAT Questions

SHARE ON FACEBOOK SHARE ON TWITTER

Comments

No Comments To Show

SUBSCRIBE TO OUR NEWS LETTER

COLLEGE NOTIFICATIONS

EXAM NOTIFICATIONS

NEWS UPDATES

Download the Collegedunia app on

BITSAT PYQs for Distance of a Point From a Line with Solutions: Practice BITSAT Previous Year Questions

BITSAT PYQs for Distance of a Point From a Line with Solutions

1.
If a point $ P(x, y) $ satisfies the condition that its distance from the point $ (3, -2) $ is equal to its distance from the line $ y = 2x + 1 $, then the locus of point $ P $ is:

2.
The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line $$ 4x - 5y = 20 $$ to the circle $$ x^2 + y^2 = 9 \text{ is:} $$

3.
A normal is drawn at the point \( P \) to the parabola \( y^2 = 8x \), which is inclined at \( 60^\circ \) with the straight line \( y = 8 \). Then the point \( P \) lies on the straight line:

4.
The nearest point on the line $3x + 4y = 12$ from the origin is

Comments

SUBSCRIBE TO OUR NEWS LETTER

BITSAT PYQs for Distance of a Point From a Line with Solutions

1.If a point $ P(x, y) $ satisfies the condition that its distance from the point $ (3, -2) $ is equal to its distance from the line $ y = 2x + 1 $, then the locus of point $ P $ is:

2.The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line $$ 4x - 5y = 20 $$ to the circle $$ x^2 + y^2 = 9 \text{ is:} $$

3.A normal is drawn at the point \( P \) to the parabola \( y^2 = 8x \), which is inclined at \( 60^\circ \) with the straight line \( y = 8 \). Then the point \( P \) lies on the straight line:

4.The nearest point on the line $3x + 4y = 12$ from the origin is

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If a point $ P(x, y) $ satisfies the condition that its distance from the point $ (3, -2) $ is equal to its distance from the line $ y = 2x + 1 $, then the locus of point $ P $ is:

2.
The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line $$ 4x - 5y = 20 $$ to the circle $$ x^2 + y^2 = 9 \text{ is:} $$

3.
A normal is drawn at the point \( P \) to the parabola \( y^2 = 8x \), which is inclined at \( 60^\circ \) with the straight line \( y = 8 \). Then the point \( P \) lies on the straight line:

4.
The nearest point on the line $3x + 4y = 12$ from the origin is