BITSAT PYQs for Simple Harmonic Motion with Solutions: Practice BITSAT Previous Year Questions

Updated 3+ months ago

Simple Harmonic Motion is an important topic in the Physics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.

This article gives you a full set of BITSAT PYQs for Simple Harmonic Motion with explanations for effective preparation. Practice of BITSAT Physics PYQs including Simple Harmonic Motion questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.

BITSAT PYQs for Simple Harmonic Motion with Solutions

1.
The displacement of a particle is given at time $t$, by $x=A \sin (-2 \omega t)+B \sin ^{2} \omega t$ Then
- the motion of the particle is SHM with an amplitude of $\sqrt{A^{2}+\frac{B^{2}}{4}}$
- the motion of the particle is not SHM, but oscillatory with a time period of $T = \pi \omega$
- the motion of the particle is oscillatory with a time period of $T = \pi \, 2\omega$
- the motion of the particle is a periodic.
View Solution
2.
The amplitude of a damped oscillator becomes $\left(\frac{1}{3}\right)rd$ in $2$ seconds. If its amplitude after $6$ seconds is $\frac{1}{n}$ times the original amplitude, the value of $n$ is
- $3^2$
- $3^3$
- $3 \sqrt{2}$
- $2^3$
View Solution
3.
A simple pendulum performing small oscillations at a height R above Earth's surface has a time period of $T_1 = 4$ s. What would be its time period at a point which is at a height $2R$ from Earth's surface?
- $T_1 = T_2$
- $2T_1 = 3T_2$
- $3T_1 = 2T_2$
- $2T_1 = T_2$
View Solution
4.
A particle on the trough of a wave at any instant will come to the mean position after a time : ($T =$ time period)
- T/2
- T/4
- T
- 2T
View Solution
5.
A particle of mass $m$ executes simple harmonic motion with amplitude a and frequency $n$. The average kinetic energy during its motion from the position of equilibrium to the end is.
- $2\pi^2 ma^2 v^2$
- $\pi ^2 ma^2 v^2 $
- $\frac{1}{4} ma^2 v^2$
- $4\pi ^2 ma^2 v^2 $
View Solution
6.
Two particles $P$ and $Q$ describe S.H.M. of same amplitude a, same frequency $f$ along the same straight line. The maximum distance between the two particles is $a \sqrt{2}$ The initial phase difference between the particle is
- zero
- $\pi /2$
- $\pi /6$
- $\pi /3$
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BITSAT PYQs for Simple Harmonic Motion with Solutions

1.The displacement of a particle is given at time $t$, by $x=A \sin (-2 \omega t)+B \sin ^{2} \omega t$ Then

2.The amplitude of a damped oscillator becomes $\left(\frac{1}{3}\right)rd$ in $2$ seconds. If its amplitude after $6$ seconds is $\frac{1}{n}$ times the original amplitude, the value of $n$ is

3.A simple pendulum performing small oscillations at a height R above Earth's surface has a time period of \(T_1 = 4\) s. What would be its time period at a point which is at a height \(2R\) from Earth's surface?

4.A particle on the trough of a wave at any instant will come to the mean position after a time : ($T =$ time period)

5.A particle of mass $m$ executes simple harmonic motion with amplitude a and frequency $n$. The average kinetic energy during its motion from the position of equilibrium to the end is.

6.Two particles $P$ and $Q$ describe S.H.M. of same amplitude a, same frequency $f$ along the same straight line. The maximum distance between the two particles is $a \sqrt{2}$ The initial phase difference between the particle is

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1.
The displacement of a particle is given at time $t$, by $x=A \sin (-2 \omega t)+B \sin ^{2} \omega t$ Then

2.
The amplitude of a damped oscillator becomes $\left(\frac{1}{3}\right)rd$ in $2$ seconds. If its amplitude after $6$ seconds is $\frac{1}{n}$ times the original amplitude, the value of $n$ is

3.
A simple pendulum performing small oscillations at a height R above Earth's surface has a time period of \(T_1 = 4\) s. What would be its time period at a point which is at a height \(2R\) from Earth's surface?

4.
A particle on the trough of a wave at any instant will come to the mean position after a time : ($T =$ time period)

5.
A particle of mass $m$ executes simple harmonic motion with amplitude a and frequency $n$. The average kinetic energy during its motion from the position of equilibrium to the end is.

6.
Two particles $P$ and $Q$ describe S.H.M. of same amplitude a, same frequency $f$ along the same straight line. The maximum distance between the two particles is $a \sqrt{2}$ The initial phase difference between the particle is