CBSE Class 12th Board Mathematics exam was conducted on 8th March 2025 from 10:30 AM to 1:30 PM.The Mathematics theory paper is worth 80 marks, and the internal assessment is worth 20 marks. The CBSE Mathematics question paper includes MCQ (1 mark each), short-answer type questions (2 and 3 marks each), and long-answer type questions (4 and 6 marks each), totaling 80 marks.
CBSE Class 12 2025 Mathematics 65-4-1 question paper with Solution PDF is available here for download.
CBSE Class 12 2025 Mathematics 65-4-1 Question Paper with Solution PDF
| CBSE Class 12 2025 Mathematics Question Paper with Answer Key | Download PDF | Check Solutions |

The principal value of \(\sin^{-1} \left( \sin \left( -\frac{10\pi}{3} \right) \right)\) is :
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If A and B are square matrices of same order such that AB = BA, then \(A^2 + B^2\) is equal to :
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For real \(x\), let \(f(x) = x^3 + 5x + 1\). Then :
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If \(y = \sin^{-1} x\), then \((1 - x^2) \frac{d^2y}{dx^2}\) is equal to :
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The values of \(\lambda\) so that \(f(x) = \sin x - \cos x - \lambda x + C\) decreases for all real values of \(x\) are :
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If P is a point on the line segment joining \((3, 6, -1)\) and \((6, 2, -2)\) and the \(y\)-coordinate of P is 4, then its \(z\)-coordinate is :
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If \(M\) and \(N\) are square matrices of order 3 such that \(\det(M) = m\) and \(MN = mI\), then \(\det(N)\) is equal to :
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If \(f(x) = \begin{cases} 3x - 2, & 0 \leq x \leq 1
2x^2 + ax, & 1 < x < 2 \end{cases}\) is continuous for \(x \in (0, 2)\), then \(a\) is equal to :
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If \(f : \mathbb{N} \rightarrow \mathbb{W}\) is defined as \[ f(n) = \begin{cases} \frac{n}{2}, & if n is even
0, & if n is odd \end{cases} \]
then \(f\) is :
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The matrix \[ \begin{pmatrix} 0 & 1 & -2
-1 & 0 & -7
2 & 7 & 0 \end{pmatrix} \]
is a :
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If the sides \(AB\) and \(AC\) of \(\triangle ABC\) are represented by vectors \(\hat{i} + \hat{j} + 4 \hat{k}\) and \(3 \hat{i} - \hat{j} + 4 \hat{k}\) respectively, then the length of the median through A on BC is :
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The function \(f\) defined by \[ f(x) = \begin{cases} x, & if x \leq 1
5, & if x > 1 \end{cases} \]
is not continuous at :
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If \(f(x) = 2x + \cos x\), then \(f(x)\) :
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\[ \int \frac{\cos 2x - \cos 2\alpha}{\cos x - \cos \alpha} \, dx \]
is equal to :
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The value of \[ \int_0^1 \frac{dx}{e^x + e^{-x}} \]
is :
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The order and degree of the differential equation \[ \left( \frac{d^2y}{dx^2} \right)^2 + \left( \frac{dy}{dx} \right)^2 = x \sin \left( \frac{dy}{dx} \right) \]
are :
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The area of the region enclosed by the curve \(y = \sqrt{x}\) and the lines \(x = 0\) and \(x = 4\) and the x-axis is :
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The corner points of the feasible region of a Linear Programming Problem are \((0, 2)\), \((3, 0)\), \((6, 0)\), \((6, 8)\), and \((0, 5)\). If \(Z = ax + by; \, (a, b > 0)\) be the objective function, and maximum value of \(Z\) is obtained at \((0, 2)\) and \((3, 0)\), then the relation between \(a\) and \(b\) is :
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Assertion (A): If A and B are two events such that \(P(A \cap B) = 0\), then A and B are independent events.
Reason (R): Two events are independent if the occurrence of one does not affect the occurrence of the other.
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Assertion (A): In a Linear Programming Problem, if the feasible region is empty, then the Linear Programming Problem has no solution.
Reason (R): A feasible region is defined as the region that satisfies all the constraints.
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Let A and B be two square matrices of order 3 such that \(det(A) = 3\) and \(det(B) = -4\). Find the value of \(det(-6AB)\).
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(a) Find the least value of ‘a’ so that \(f(x) = 2x^2 - ax + 3\) is an increasing function on \([2, 4]\).
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(b) If \(f(x) = x + \frac{1}{x}, \, x \geq 1\), show that \(f\) is an increasing function.
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(a) Simplify \(\sin^{-1} \left( \frac{x}{\sqrt{1 + x^2}} \right)\).
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(b) Find the domain of \(\sin^{-1} \sqrt{x - 1}\).
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Calculate the area of the region bounded by the curve \[ \frac{x^2}{9} + \frac{y^2}{4} = 1 \]
and the x-axis using integration.
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For the curve \( y = 5x - 2x^3 \), if \( x \text{ increases at the rate of 2 \text{ units/s, \text{ then how fast is the slope of the curve changing when x = 2?
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If \(f : \mathbb{R}^+ \to \mathbb{R}\) is defined as \(f(x) = \log_a x\) where \(a > 0\) and \(a \neq 1\), prove that \(f\) is a bijection.
(R\(^+\) is the set of all positive real numbers.)
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Let \(A = \{1, 2, 3\}\) and \(B = \{4, 5, 6\}\). A relation \(R\) from \(A\) to \(B\) is defined as \(R = \{(x, y) : x + y = 6, x \in A, y \in B \}\).
(i) Write all elements of \(R\).
(ii) Is \(R\) a function? Justify.
(iii) Determine domain and range of \(R\).
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Find \(k\) so that \[ f(x) = \begin{cases} \frac{x^2 - 2x - 3}{x + 1}, & if x \neq -1
k, & if x = -1 \end{cases} \]
is continuous at \(x = -1\).
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Check the differentiability of the function \(f(x) = |x|\) at \(x = 0\).
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Evaluate: \[ \int_{\frac{\pi}{2}}^{\pi} \frac{e^{x} \left(1 - \sin x \right)}{1 - \cos x} \, dx. \]
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Find the probability distribution of the number of boys in families having three children, assuming equal probability for a boy and a girl.
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A coin is tossed twice. Let \(X\) be a random variable defined as the number of heads minus the number of tails. Obtain the probability distribution of \(X\) and also find its mean.
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Find the distance of the point \((-1, -5, -10)\) from the point of intersection of the lines \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4}, \quad \frac{x - 4}{5} = \frac{y - 1}{2} = z. \]
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Solve the following Linear Programming Problem using graphical method :
Maximize \( Z = 100x + 50y \)
subject to the constraints \[ 3x + y \leq 600, \quad x + y \leq 300, \quad y \leq x + 200, \quad x \geq 0, \quad y \geq 0. \]
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The relation between the height of the plant (\(y\) cm) with respect to exposure to sunlight is governed by the equation \[ y = 4x - \frac{1}{2} x^2, \]
where \(x\) is the number of days exposed to sunlight.
(i) Find the rate of growth of the plant with respect to sunlight.
(ii) In how many days will the plant attain its maximum height? What is the maximum height?
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Find: \[ \int \frac{\cos x}{(4 + \sin^2 x)(5 - 4 \cos^2 x)} \, dx. \]
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Evaluate: \[ \int_0^\pi \frac{dx}{a^2 \cos^2 x + b^2 \sin^2 x}. \]
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Show that the area of a parallelogram whose diagonals are represented by \( \vec{a} \) and \( \vec{b} \) is given by \[ Area = \frac{1}{2} | \vec{a} \times \vec{b} |. \]
Also, find the area of a parallelogram whose diagonals are \( 2\hat{i} - \hat{j} + \hat{k} \) and \( \hat{i} + 3\hat{j} - \hat{k} \).
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Find the equation of a line in vector and Cartesian form which passes through the point \( (1, 2, -4) \) and is perpendicular to the lines \[ \frac{x - 8}{3} = \frac{y + 19}{-16} = \frac{z - 10}{7}. \]
and \[ \vec{r} = 15\hat{i} + 29\hat{j} + 5\hat{k} + \mu (3\hat{i} + 8\hat{j} - 5\hat{k}). \]
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