The CBSE conducted the Class 12 Physics Board Exam on February 21, 2025, from 10:30 AM to 1:30 PM. The Physics theory paper has 70 marks, while 30 marks are allocated for the practical assessment.

The question paper includes multiple-choice questions (1 mark each), short-answer questions (2-3 marks each), and long-answer questions (5 marks each).

CBSE Class 12 Physics 55-6-2 Question Paper and Detailed Solutions PDF is available for download here.

CBSE Class 12 2025 Physics 55-6-2 Question Paper with Solution PDF

CBSE Class 12 Physics Question Paper With Answer Key Download Check Solutions

CBSE Board Class 12 2025 Physics 55 6 2 Question Paper with Solutions


Question 1:

A wire of resistance \( R \), connected to an ideal battery, consumes a power \( P \). If the wire is gradually stretched to double its initial length, and connected across the same battery, the power consumed will be:

  • (A) \( \frac{P}{4} \)
  • (B) \( \frac{P}{2} \)
  • (C) \( P \)
  • (D) \( 2P \)
Correct Answer: (A) \( \frac{P}{4} \)
View Solution

Question 2:

A vertically held bar magnet is dropped along the axis of a copper ring having a cut as shown in the diagram. The acceleration of the falling magnet is:


  • (A) zero
  • (B) less than \( g \)
  • (C) \( g \)
  • (D) greater than \( g \)
Correct Answer: (C) \( g \)
View Solution

Question 3:

A straight conductor is carrying a current of 2 A in the \( +x \) direction along it. A uniform magnetic field \( \vec{B} = (0.6 \hat{j} + 0.8 \hat{k}) \) T is switched on in the region. The force acting on 10 cm length of the conductor is:

  • (A) \( (0.12 \hat{j} - 0.16 \hat{k}) \, N \)
  • (B) \( (-0.16 \hat{j} + 0.12 \hat{k}) \, N \)
  • (C) \( (-0.12 \hat{j} + 0.16 \hat{k}) \, N \)
  • (D) \( (0.16 \hat{j} - 0.12 \hat{k}) \, N \)
Correct Answer: (B) \( (-0.16 \hat{j} + 0.12 \hat{k}) \, \text{N} \)
View Solution

Question 4:

An ac source is connected to a resistor and an inductor in series. The voltage across the resistor and inductor are 8 V and 6 V respectively. The voltage of the source is:

  • (A) 10 V
  • (B) 12 V
  • (C) 14 V
  • (D) 16 V
Correct Answer: (A) 10 V
View Solution

Question 5:

A proton and an \( \alpha \)-particle enter with the same velocity \( \vec{v} \) in a uniform magnetic field \( \vec{B} \) such that \( \vec{v} \perp \vec{B} \). The ratio of the radii of their paths is:

  • (A) 2
  • (B) \( \frac{1}{2} \)
  • (C) \( \frac{1}{4} \)
  • (D) 4
Correct Answer: (B) \( \frac{1}{2} \)
View Solution

Question 6:

Two coherent waves, each of intensity \( I_0 \), produce an interference pattern on a screen. The average intensity of light on the screen is:

  • (A) zero
  • (B) \( I_0 \)
  • (C) \( 2I_0 \)
  • (D) \( 4I_0 \)
Correct Answer: (C) \( 2I_0 \)
View Solution




When two coherent waves of equal intensity \( I_0 \) interfere, the resulting intensity depends on the phase difference between them.

The intensity \( I \) at any point due to two interfering waves can be given by: \[ I = I_1 + I_2 + 2 \sqrt{I_1 I_2} \cos(\phi) \]
where:
- \( I_1 = I_2 = I_0 \) are the intensities of the two waves,
- \( \phi \) is the phase difference between the two waves.

For constructive interference (when the waves are in phase, i.e., \( \phi = 0 \)): \[ I = I_0 + I_0 + 2 \sqrt{I_0 I_0} \cos(0) = 2I_0 + 2I_0 = 4I_0 \]

For destructive interference (when the waves are out of phase, i.e., \( \phi = \pi \)): \[ I = I_0 + I_0 + 2 \sqrt{I_0 I_0} \cos(\pi) = 2I_0 - 2I_0 = 0 \]

The average intensity is the mean of the maximum and minimum intensities. Since the maximum intensity is \( 4I_0 \) and the minimum intensity is 0, the average intensity is: \[ I_{avg} = \frac{4I_0 + 0}{2} = 2I_0 \]

Thus, the average intensity on the screen is \( 2I_0 \). Quick Tip: In interference patterns, the intensity varies depending on the phase difference between the two waves. The average intensity is the mean of the maximum and minimum intensities observed.


Question 7:

If \( R_s \) and \( R_p \) are the equivalent resistances of \( n \) resistors, each of value \( R \), in series and parallel combinations respectively, then the value of \( (R_s - R_p) \) is:

  • (A) \( \left( \frac{n^2 - 1}{n^2} \right) R \)
  • (B) \( \left( \frac{n^2 + 1}{n^2 - 1} \right) R \)
  • (C) \( \left( \frac{n^2 - 1}{n} \right) R \)
  • (D) \( \frac{(n^2 + 1)}{n^2} R \)
Correct Answer: (C) \( \left( \frac{n^2 - 1}{n} \right) R \)
View Solution

Question 8:

A galvanometer can be converted into an ammeter of desired range by connecting a:

  • (A) small resistance in series
  • (B) large resistance in series
  • (C) small resistance in parallel
  • (D) large resistance in parallel
Correct Answer: (D) large resistance in parallel
View Solution

Question 9:

Inside a nucleus, the nuclear forces between proton and proton, proton and neutron, neutron and neutron are \( F_{pp} \), \( F_{pn} \) and \( F_{nn} \) respectively. Then:

  • (A) \( F_{pp} > F_{pn} > F_{nn} \)
  • (B) \( F_{pn} > F_{nn} > F_{pp} \)
  • (C) \( F_{nn} > F_{pp} > F_{pn} \)
  • (D) \( F_{pp} = F_{pn} = F_{nn} \)
Correct Answer: (D) \( F_{pp} = F_{pn} = F_{nn} \)
View Solution

Question 10:

The de Broglie wavelength associated with an electron moving with energy 5 eV is:

  • (A) 0.75 nm
  • (B) 1.2 nm
  • (C) 2.4 nm
  • (D) 0.55 nm
Correct Answer: (D) 0.55 nm
View Solution

Question 11:

The de Broglie wavelength associated with an electron moving with energy 5 eV is:

  • (A) 0.75 nm
  • (B) 1.2 nm
  • (C) 2.4 nm
  • (D) 0.55 nm
Correct Answer: (D) 0.55 nm
View Solution

Question 12:

A piece of a diamagnetic material, free to move when placed in a uniform magnetic field:

  • (A) moves along the field
  • (B) moves opposite to the field
  • (C) moves perpendicular to the field
  • (D) does not move at all
Correct Answer: (D) does not move at all
View Solution

Question 13:

The momentum (in kg m/s) of a photon of frequency \( 6.0 \times 10^{14} \) Hz is:

  • (A) \( 6.63 \times 10^{-25} \)
  • (B) \( 1.326 \times 10^{-27} \)
  • (C) \( 2.652 \times 10^{-26} \)
  • (D) \( 3.978 \times 10^{-24} \)
Correct Answer: (B) \( 1.326 \times 10^{-27} \)
View Solution




The momentum of a photon is related to its frequency \( \nu \) by the following equation: \[ p = \frac{h \nu}{c} \]
where:
- \( p \) is the momentum of the photon,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, J \cdot s \)),
- \( \nu \) is the frequency of the photon,
- \( c \) is the speed of light (\( 3.0 \times 10^8 \, m/s \)).

Substituting the given values:
- \( \nu = 6.0 \times 10^{14} \, Hz \),
- \( h = 6.626 \times 10^{-34} \, J \cdot s \),
- \( c = 3.0 \times 10^8 \, m/s \),

we get: \[ p = \frac{6.626 \times 10^{-34} \times 6.0 \times 10^{14}}{3.0 \times 10^8} \] \[ p = \frac{3.9756 \times 10^{-19}}{3.0 \times 10^8} \] \[ p = 1.326 \times 10^{-27} \, kg \cdot m/s \]

Thus, the correct answer is \( 1.326 \times 10^{-27} \, kg \cdot m/s \). Quick Tip: The momentum of a photon is directly related to its frequency and inversely related to the speed of light. The higher the frequency of the photon, the greater its momentum.


Question 14:

Two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below.

Assertion (A): A hole is an apparent free particle with effective positive electronic charge.

Reason (R): A hole is not necessarily a vacancy left behind by an electron in the valence band.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Both Assertion (A) and Reason (R) are false.
Correct Answer: (C) Assertion (A) is true, but Reason (R) is false.
View Solution

Question 15:

Two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below.

Assertion (A): In a reflecting telescope, the image does not have chromatic aberration.

Reason (R): Chromatic aberration occurs only due to refraction of light through an optical medium.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Both Assertion (A) and Reason (R) are false.
Correct Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
View Solution

Question 16:

Two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below.

Assertion (A): The binding energy per nucleon is practically constant for mass number in the range \( 30 < A < 170 \).

Reason (R): Nuclear forces between the nucleons for mass numbers in the range \( 30 < A < 170 \) are not short-range.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Both Assertion (A) and Reason (R) are false.
Correct Answer: (C) Assertion (A) is true, but Reason (R) is false.
View Solution

Question 17:

Two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below.

Assertion (A): X-rays are produced when slow moving electrons are stopped by a metal target of high atomic number.

Reason (R): X-rays consist of low-energy photons.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Both Assertion (A) and Reason (R) are false.
Correct Answer: (D) Both Assertion (A) and Reason (R) are false.
View Solution

Question 18:

A cell of emf \( E \) and internal resistance \( r \) is connected to an external variable resistance \( R \). Plot a graph showing the variation of terminal voltage \( V \) of the cell as a function of current \( I \), supplied by the cell. Explain how the emf of the cell and its internal resistance can be found from it.

Correct Answer:
View Solution

Question 19:

In an n-type semiconductor, electron-hole combination is a continuous process at room temperature. Yet the electron concentration is always greater than the hole concentration in it. Explain.

Correct Answer:
View Solution

Question 20:

A laser beam of wavelength 500 nm and power 5 mW strikes normally on a perfectly reflecting surface of area 1 mm\(^2\) of a body. It rebounds back from the surface. Find the force exerted by the laser beam on the body.

Correct Answer:
View Solution

Question 21:

A ray of light is incident on face AB of a prism ABC with angle of prism \( A \) and emerges out from face AC. The prism is set in the position of minimum deviation with angle of deviation \( \delta \). Find:

the angle of incidence and
the angle of refraction on face AB.

Correct Answer:
View Solution

Question 22:

(a) Define the term 'drift velocity' of conduction electrons in a conductor.

Correct Answer:
View Solution

Question 23:

(a) State Lenz's law. A rod MN of length \( L \) is rotated about an axis passing through its end \( M \) perpendicular to its length, with a constant angular velocity \( \omega \) in a uniform magnetic field \( \vec{B} \) parallel to the axis. Obtain an expression for the emf induced between its ends.

Correct Answer:
View Solution

Question 24:

A ray of light is incident at an angle \( i \) on a parallel sided glass slab of thickness \( d \) and gets refracted into the slab at angle \( r \). Draw a ray diagram to show its path as it emerges out of the slab. Hence, obtain an expression for the lateral shift of the ray. Under what condition will the shift be minimum?

Correct Answer:
View Solution

Question 25:

Describe briefly the Geiger-Marsden scattering experiment. Depict the graph showing the variation of the number of scattered particles detected with the scattering angle. How did this graph lead to the discovery of the nucleus?

Correct Answer:
View Solution

Question 26:

A rectangular loop carries a current of 1 A. A straight long wire carrying 2 A current is kept near the loop in the same plane as shown in the figure.




Find:

(i) the torque acting on the loop, and

(ii) the magnitude and direction of the net force on the loop.

Correct Answer:
View Solution

Question 27:

Name the electromagnetic wave used (i) in radar, (ii) in eye surgery, and (iii) as a diagnostic tool in medicine. Write their wavelength range also.

Correct Answer:
View Solution

Question 28:

Which of the following is a donor impurity atom for Ge?

  • (A) Boron
  • (B) Antimony
  • (C) Aluminium
  • (D) Indium
Correct Answer: (B) Antimony
View Solution

Question 29:

When a pentavalent atom occupies the position of an atom in the crystal lattice of Si, four of its electrons form covalent bonds with four silicon neighbours, while the fifth remains bound to the parent atom. The energy required to set this electron free is about:

  • (A) 0.5 eV
  • (B) 0.1 eV
  • (C) 0.05 eV
  • (D) 0.01 eV
Correct Answer: (C) 0.05 eV
View Solution

Question 30:

During formation of a p-n junction:

  • (A) a layer of negative charge on n-side and a layer of positive charge on p-side appear.
  • (B) a layer of positive charge on n-side and a layer of negative charge on p-side appear.
  • (C) the electrons on p-side of the junction move to n-side initially.
  • (D) initially diffusion current is small and drift current is large.
Correct Answer: (C) the electrons on p-side of the junction move to n-side initially.
View Solution

Question 31:

In reverse-biased p-n junction:

  • (A) the drift current is of the order of few mA
  • (B) the applied voltage mostly drops across the depletion region.
  • (C) the depletion region width decreases.
  • (D) the current increases with increase in applied voltage.
Correct Answer: (B) the applied voltage mostly drops across the depletion region.
View Solution

Question 32:

The output frequency of a full-wave rectifier with 50 Hz as input frequency is:

  • (A) 25 Hz
  • (B) 50 Hz
  • (C) 100 Hz
  • (D) 200 Hz
Correct Answer: (C) 100 Hz
View Solution

Question 33:

In reverse-biased p-n junction:

  • (A) the drift current is of the order of few mA
  • (B) the applied voltage mostly drops across the depletion region.
  • (C) the depletion region width decreases.
  • (D) the current increases with increase in applied voltage.
Correct Answer: (B) the applied voltage mostly drops across the depletion region.
View Solution

Question 34:

The output frequency of a full-wave rectifier with 50 Hz as input frequency is:

  • (A) 25 Hz
  • (B) 50 Hz
  • (C) 100 Hz
  • (D) 200 Hz
Correct Answer: (C) 100 Hz
View Solution

Question 35:

Consider a capacitor of capacitance \( C \), with plate area \( A \) and plate separation \( d \), filled with air [Fig. (a)]. The distance between the plates is increased to \( 2d \) and one of the plates is shifted as shown in Fig. (b). The capacitance of the new system now is:



% option
(A) \( \frac{C}{4} \)

  • (B) \( \frac{C}{2} \)
  • (C) \( 2C \)
  • (D) \( 4C \)
Correct Answer: (A) \( \frac{C}{4} \)
View Solution




In this problem, we have a parallel plate capacitor with a capacitance \( C \) when the plates are separated by a distance \( d \). The capacitance \( C \) of a parallel plate capacitor is given by the formula: \[ C = \frac{\epsilon_0 A}{d} \]
where \( \epsilon_0 \) is the permittivity of free space, \( A \) is the area of the plates, and \( d \) is the distance between the plates.

When the distance between the plates is increased from \( d \) to \( 2d \), the capacitance will decrease because capacitance is inversely proportional to the distance between the plates. However, one of the plates is shifted, which changes the effective area of the capacitor. The shift reduces the effective area of overlap between the plates.

The capacitance can be expressed as: \[ C' = \frac{\epsilon_0 A'}{2d} \]
where \( A' \) is the effective overlapping area, which is now reduced. In this case, due to the plate shift, the effective overlapping area is halved. Thus, the new capacitance is given by: \[ C' = \frac{C}{4} \]

Therefore, the correct answer is \( \frac{C}{4} \). Quick Tip: When the distance between the plates of a parallel plate capacitor is increased, the capacitance decreases. Additionally, if the effective area of overlap is reduced (as in this case where one plate is shifted), the capacitance is further reduced.


Question 36:

A slab (area A and thickness \( d_1 \)) of a linear dielectric of dielectric constant \( K \) is inserted between charged plates (charge density \( \sigma \)) of a parallel plate capacitor [plate area A and plate separation \( d > d_1 \)] and opposite charges with charge density of magnitude \( \sigma_p \) appear on the faces of the slab. The dielectric constant K is given by:

  • (A) \( \frac{\sigma + \sigma_p}{\sigma} \)
  • (B) \( \frac{\sigma}{\sigma - \sigma_p} \)
  • (C) \( \frac{\sigma + \sigma_p}{\sigma_p} \)
  • (D) \( \frac{\sigma}{\sigma_p} \)
Correct Answer: (A) \( \frac{\sigma + \sigma_p}{\sigma} \)
View Solution

Question 37:

An electric field \( E \) is established between the plates of an air-filled parallel plate capacitor, with charges \( Q \) and \( -Q \). \( V \) is the volume of the space enclosed between the plates. The energy stored in the capacitor is:

  • (A) \( \frac{1}{2} \epsilon_0 E^2 \)
  • (B) \( \epsilon_0 Q^2 E \)
  • (C) \( \frac{1}{2} \epsilon_0 E^2 V \)
  • (D) \( \epsilon_0 E Q V \)
Correct Answer: (C) \( \frac{1}{2} \epsilon_0 E^2 V \)
View Solution

Question 38:

Three capacitors A, B, and M, each of capacitance \( C \), are connected to a capacitor N of capacitance \( 2C \) and a battery as shown in the figure. If the charges on A and N are \( Q \) and \( Q' \) respectively, then \( \frac{Q'}{Q} \) is:


  • (A) \( \frac{1}{6} \)
  • (B) \( \frac{1}{3} \)
  • (C) 3
  • (D) \( \frac{7}{3} \)
Correct Answer: (D) \( \frac{7}{3} \)
View Solution

Question 39:

A slab (area A and thickness \( \frac{d}{2} \)) of dielectric constant \( K \) is inserted in a parallel plate capacitor of plate area \( A \) and plate separation \( d \). If \( C \) and \( C_0 \) are the capacitances of the capacitors with and without the dielectric, then \( \frac{C}{C_0} \) is:

  • (A) \( \frac{K + 1}{2K} \)
  • (B) \( \frac{2K}{K + 1} \)
  • (C) \( \frac{K}{K - 1} \)
  • (D) \( \frac{K - 1}{K} \)
Correct Answer: (B) \( \frac{2K}{K + 1} \)
View Solution

Question 40:

(i) Draw a ray diagram to show the image formation by a compound microscope. Obtain the expression for the total magnification of the microscope when the final image is formed at infinity.

Correct Answer:
View Solution

N/A


Question 41:

In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. The eyepiece has a focal length of 5 cm. The final image is formed at infinity. Calculate the distance between the objective and the eyepiece.

Correct Answer:
View Solution

Question 42:

(i) Using Huygens’ principle, explain the refraction of a plane wavefront, propagating in air, at a plane interface between air and glass. Hence verify Snell’s law.

Correct Answer:
View Solution

N/A


Question 43:

Use the mirror formula to deduce that a convex mirror always produces a virtual image of an object kept in front of it.

Correct Answer:
View Solution

Question 44:

(i) The electric field in a region is given by \( \vec{E} = 40x \hat{i} \, N/C. \) Find the amount of work done in taking a unit positive charge from a point (0, 3m) to the point (5m, 0).

Correct Answer:
View Solution

Question 45:

A charge \( Q \) is distributed over two concentric hollow spheres of radii \( r \) and \( R \) (\( R > r \)) such that their surface charge densities are equal. Find:

the electric field, and
the potential at their common center.

Correct Answer:
View Solution

Question 46:

Obtain an expression for the electric field \( \vec{E} \) due to a dipole of dipole moment \( \vec{p} \) at a point on its equatorial plane and specify its direction. Hence, find the value of electric field:

at the centre of the dipole (\( r = 0 \)), and
at a point \( r \gg a \), where \( 2a \) is the length of the dipole.

Correct Answer:
View Solution

Question 47:

An electric field \( \vec{E} = (10x + 5) \hat{i} \, N/C \) exists in a region in which a cube of side \( L \) is kept as shown in the figure. Here \( x \) and \( L \) are in metres. Calculate the net flux through the cube.


Correct Answer:
View Solution

Question 48:

(i) Write the principle of working of an ac generator. Draw its labelled diagram and explain its working.

Correct Answer:
View Solution

N/A


Question 49:

A resistor of 400 \( \Omega \), an inductor of \( \frac{5}{\pi} \) H, and a capacitor of \( \frac{50}{\pi} \) µF are joined in series across an AC source \( v = 140 \sin (100 \pi t) \) V. Find the rms voltages across these three circuit elements. The algebraic sum of these voltages is more than the rms voltage of source. Explain.

Correct Answer:
View Solution

Question 50:

Write the principle of working of a transformer. With the help of a labelled diagram, explain the working of a step-up transformer.

Correct Answer:
View Solution