CBSE Class 12 Chemistry Compartment Question Paper 2023 with Answer Key pdf (Set 1 - 56/C/1) is available for download here. The exam was conducted by Central Board of Secondary Education on July 17, 2023 in the Morning Session 10:30 AM to 1:30 PM. The question paper comprised a total of 35 questions divided among 5 sections.

CBSE Class 12 Chemistry (Set 1 - 56/C/1) Compartment Question Paper 2023 with Answer Key

CBSE Class 12 Chemistry Question Paper With Answer Key Download PDF Check Solutions
CBSE Class 12 Chemistry

Question 1:

Choose the compound which is more acidic than phenol:

  • (A) \( o-nitrophenol \)
  • (B) ethanol
  • (C) \( o-methylphenol \)
  • (D) \( o-methoxyphenol \)
Correct Answer: (A) \( o\text{-}nitrophenol \)
View Solution

Question 2:

Which of the following reactions is a halogenated exchange reaction:

  • (A) \( Alkene + HX \longrightarrow Alkane with halogen \)
  • (B) \( R{-}X + NaI \xrightarrow{Dry acetone} R{-}I + NaX \)
  • (C) \( R{-}OH + HCl \xrightarrow{ZnCl_2} R{-}Cl + H_2O \)
  • (D) Bromination of toluene with \( Br_2 \) and \( Fe \) in dark
Correct Answer: (B) \( R{-}X + NaI \longrightarrow R{-}I + NaX \)
View Solution

Question 3:

The most common oxidation state for all lanthanoids is:

  • (A) \( +5 \)
  • (B) \( +2 \)
  • (C) \( +3 \)
  • (D) \( +4 \)
Correct Answer: (C) \( +3 \)
View Solution

Question 4:

A reaction follows second order kinetics. How is the rate of reaction affected if the concentration of the reactant is reduced to half? Choose the correct value from the following:

  • (A) four times
  • (B) eight times
  • (C) \( \frac{1}{4} \) of the original value
  • (D) three times
Correct Answer: (C) \( \frac{1}{4} \) of the original value
View Solution

Question 5:

Solutions of two electrolytes X and Y are diluted. Molar conductivity of X increases 25 times whereas that of Y increases 1.5 times. Which one is a stronger electrolyte?

  • (A) X
  • (B) Y
  • (C) Both X and Y
  • (D) None of the above
Correct Answer: (B) Y
View Solution

Question 6:

Unit of rate constant for the zero order reaction is:

  • (A) \( s^{-1} \)
  • (B) \( mol^{-1} L\, s^{-1} \)
  • (C) \( mol^{-2} L^{2} s^{-1} \)
  • (D) \( mol\, L^{-1} s^{-1} \)
Correct Answer: (4) \( mol\, L^{-1} s^{-1} \)
View Solution

Question 7:

Three compounds are given below:


The correct decreasing order of their basic strength is:

  • (A) II \(>\) III \(>\) I
  • (B) III \(>\) II \(>\) I
  • (C) III \(>\) I \(>\) II
  • (D) I \(>\) III \(>\) II
Correct Answer: (1) II \(>\) III \(>\) I
View Solution

Question 8:

Which type of isomerism is shown by the complexes \([Co(NH_3)_5Br]SO_4\) and \([Co(NH_3)_5SO_4]Br\) ?

  • (A) Linkage
  • (B) Ionisation
  • (C) Optical
  • (D) Solvate
Correct Answer: (2) Ionisation
View Solution

Question 9:

What would be the major product of the given reaction?
\[ HCHO + CH_3MgI \xrightarrow{H_2O} \; ? \]

  • (A) Ethanal
  • (B) Propanol
  • (C) Ethanol
  • (D) Propanal
Correct Answer: (3) Ethanol
View Solution

Question 10:

Pentan-2-one and Pentan-3-one can be distinguished by:

  • (A) Fehling’s test
  • (B) Sodium bicarbonate test
  • (C) Tollens’ test
  • (D) Iodoform test
Correct Answer: (4) Iodoform test
View Solution

Question 11:

Hoffmann Bromamide Degradation reaction is given by:

  • (A) Nitrobenzene
  • (B) Benzamide
  • (C) Methyl cyanide
  • (D) Propanamide
Correct Answer: (4) Propanamide
View Solution

Question 12:

Given below is the decomposition of hydrogen peroxide in alkaline medium, which is catalysed by iodide ions:
\[ 2H_2O_2 \xrightarrow{I^-, \; alkaline medium} 2H_2O + O_2 \]

The above reaction takes place in two steps:


Step I: \( H_2O_2 + I^- \longrightarrow H_2O + IO^- \) (slow)

Step II: \( H_2O_2 + IO^- \longrightarrow H_2O + I^- + O_2 \)


Molecularity of Step I and Step II is:

  • (A) Step I – 2, Step II – 2
  • (B) Step I – 1, Step II – 2
  • (C) Step I – 2, Step II – 1
  • (D) Step I – 3, Step II – 1
Correct Answer: (1) Step I – 2, Step II – 2
View Solution

Question 13:

Oxidation state of central metal atom in the given complex is:
\[ [Co(NH_3)_4(H_2O)_2]Cl_3 \]

  • (A) \( +2 \)
  • (B) \( +3 \)
  • (C) \( +1 \)
  • (D) \( +4 \)
Correct Answer: (2) \( +3 \)
View Solution

Question 14:

A galvanic cell can behave as an electrolytic cell when:

  • (A) \( E_{cell} = E_{ext} \)
  • (B) \( E_{cell} > E_{ext} \)
  • (C) \( E_{cell} = 0 \)
  • (D) \( E_{ext} > E_{cell} \)
Correct Answer: (4) \( E_{ext} > E_{cell} \)
View Solution

Question 15:

Assertion (A): Phenol gives 2,4,6-trinitrophenol on treatment with concentrated \( HNO_3 \) and concentrated \( H_2SO_4 \).


Reason (R): –OH group in phenol is \( m \)-directing.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Assertion (A) is false, but Reason (R) is true.
Correct Answer: (3) Assertion (A) is true, but Reason (R) is false.
View Solution

Question 16:

Assertion (A): D (+)-Glucose is dextrorotatory.


Reason (R): Symbol ‘D’ represents its dextrorotatory nature.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Assertion (A) is false, but Reason (R) is true.
Correct Answer: (3) Assertion (A) is true, but Reason (R) is false.
View Solution

Question 17:

Assertion (A): Zn, Cd and Hg are not regarded as transition elements.


Reason (R): Zn, Cd and Hg do not have partially filled d-orbitals in their ground state or in any one of their common oxidation states.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Assertion (A) is false, but Reason (R) is true.
Correct Answer: (1) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
View Solution

Question 18:

Assertion (A): Benzene diazonium salt is stable and can be easily stored.


Reason (R): Benzene diazonium chloride decomposes easily.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Assertion (A) is false, but Reason (R) is true.
Correct Answer: (4) Assertion (A) is false, but Reason (R) is true.
View Solution

Question 19:

The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature.
\[ (\log 2 = 0.30,\; \log 4 = 0.60) \quad [R = 8.314\; J\, K^{-1}\, mol^{-1}] \]

Correct Answer:
View Solution

Question 20:

(b)i) Why do amino acids show amphoteric behaviour?

Correct Answer: They contain both acidic (–COOH) and basic (–NH\textsubscript{2}) functional groups.
View Solution

Question 21:

(b)(ii) What happens when D-Glucose is treated with hydroxylamine?

Correct Answer: D-Glucose forms an oxime.
View Solution

Question 22:

(i) Write the structure of 1-chloro-4-ethylcyclohexane.

Correct Answer: A cyclohexane ring with a chlorine atom at carbon-1 and an ethyl group at carbon-4.
View Solution

Question 23:

(ii) Why is sulphuric acid not used during the reactions of alcohols with KI?

Correct Answer: Because sulphuric acid oxidizes iodide (I\(^-\)) to iodine (I\(_2\)).
View Solution

Question 24:

(i) Arrange the following in increasing order of their boiling points:

1-chloropropane, 2-chloropropane, 1-chlorobutane


(A) 2-chloropropane \(<\) 1-chloropropane \(<\) 1-chlorobutane

Correct Answer: (A) 2-chloropropane \(<\) 1-chloropropane \(<\) 1-chlorobutane
View Solution

Question 25:

(ii) What is an ambident nucleophile? Give one example.

Correct Answer: An ambident nucleophile is one that can attack through two different atoms. Example: Cyanide ion (\( CN^- \)).
View Solution

Question 26:

(a) Why is \([Ti(H_2O)_6]^{3+}\) coloured?

Correct Answer: Due to \( d{-}d \) transitions within the partially filled d-orbitals of Ti\(^{3+} \).
View Solution

Question 27:

(b) Write IUPAC name of the given complex: \( K_3[Cr(C_2O_4)_3] \)

Correct Answer: Potassium tris(oxalato)chromate(III)
View Solution

Question 28:

(a) Why are iron pipes usually coated with zinc?

Correct Answer: To protect iron from rusting by sacrificial protection.
View Solution

Question 29:

(b) Why does mercury cell give a constant voltage throughout its life?

Correct Answer: Because the concentrations of reactants and products remain constant.
View Solution

Question 30:

(a) Write the mathematical relation between rate constant and half-life period of a zero order reaction.

Correct Answer: \( t_{1/2} = \frac{[R_0]}{2k} \)
View Solution

Question 31:

(b) Define Pseudo first order reaction with an example.

Correct Answer: A reaction involving two reactants but appears first order because one is in large excess.
View Solution

Question 32:

(a) Why is \( pK_a \) of ClCH\textsubscript{2COOH lower than the \( pK_a \) of CH\textsubscript{3COOH?

Correct Answer: Due to the electron-withdrawing effect of Cl atom.
View Solution

Question 33:

(b) Write the chemical equation for Hell-Volhard-Zelinsky reaction.

Correct Answer: \[ CH_3COOH + Br_2 \xrightarrow{P} CH_2BrCOOH + HBr \]
View Solution

Question 34:

Write the chemical equation for the following:

(a) Hydration of propene in presence of an acid

(b) Reaction between Ethyl bromide and C\textsubscript{2H\textsubscript{5ONa

(c) Reaction between Dimethyl ether and Hydrogen iodide

Correct Answer: (a) \[ CH_3CH=CH_2 + H_2O \xrightarrow{H^+} CH_3CH(OH)CH_3 \] (b) \[ C_2H_5Br + C_2H_5ONa \longrightarrow C_2H_5OC_2H_5 + NaBr \] (c) \[ CH_3OCH_3 + HI \longrightarrow CH_3I + CH_3OH \]
View Solution

Question 35:

Using valence bond theory, predict:

(a) Hybridisation of central metal atom of the complex \([Co(NH_3)_6]^{3+}\)

(b) Its shape and magnetic behaviour

(c) Whether it is a high spin or a low spin complex

[Atomic number: \(CO\) = 27]

Correct Answer: (a) \( d^2sp^3 \) hybridisation
(b) Octahedral shape; diamagnetic
(c) Low spin complex
View Solution

Question 36:

Give reasons for the following:

(a) Reduction with iron scrap and HCl is preferred for the preparation of amines from nitro compounds.


(b) Lower aliphatic amines are soluble in water.


(c) Pyridine is used in the acylation reaction of amines.


(d) Although amino group is o- and p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.

Correct Answer:
View Solution

Question 37:

(i) Why do tertiary alkyl halides undergo S\textsubscript{N}1 reaction at a faster rate?

Correct Answer:
View Solution

Question 38:

(ii) Define Enantiomers.

Correct Answer:
View Solution

Question 39:

(iii) Why is chloroform stored in dark coloured air tight bottles?

Correct Answer:
View Solution

Question 40:

(i) Write the major alkene that would be formed by dehydrohalogenation of 2-Bromopentane.

Correct Answer: 2-Pentene
View Solution

Question 41:

(ii) Which would undergo S\textsubscript{N}2 reaction at a faster rate and why?

Given compounds:

Compound A: CH\textsubscript{3–CH\textsubscript{2–Br

Compound B: \quad
\begin{tabular{c
CH\textsubscript{3

\quad|

CH\textsubscript{3–C–Br

\quad|

CH\textsubscript{3

\end{tabular

Correct Answer: Compound A (CH\textsubscript{3}–CH\textsubscript{2}–Br) undergoes S\textsubscript{N}2 reaction faster.
View Solution

Question 42:

(iii) Why is chlorobenzene less reactive towards nucleophilic substitution reaction?

Correct Answer: Due to resonance stabilization and partial double bond character in the C–Cl bond
View Solution

Question 43:

(a) Name the linkage which connects monosaccharide units in polysaccharides.

Correct Answer: Glycosidic bond
View Solution

Question 44:

(b) Carbohydrates are classified on the basis of their behaviour on hydrolysis. Write the hydrolysis products of sucrose.

Correct Answer: Glucose and Fructose
View Solution

Question 45:

(c) Write two differences between Amylose and Amylopectin.

Correct Answer: \textbf{Structure:} Amylose is a linear polymer, whereas Amylopectin is a branched polymer. \textbf{Solubility:} Amylose is slightly soluble in water, while Amylopectin is insoluble due to extensive branching.
View Solution

Question 46:

What are reducing sugars?

Correct Answer: Sugars that can reduce Tollens’ or Fehling’s reagent due to the presence of a free aldehyde or ketone group.
View Solution

Question 47:

Sucrose is dextrorotatory but the mixture obtained after hydrolysis is laevorotatory. Why?

Correct Answer: Due to the higher specific rotation of laevorotatory fructose compared to dextrorotatory glucose.
View Solution

Question 48:

(a) 20 mL of a liquid A was mixed with 20 mL of liquid B. The volume of resulting solution was found to be less than 40 mL. What do you conclude from the above data?

Correct Answer: The solution shows \textbf{negative deviation} from ideal behaviour.
View Solution

Question 49:

(b) Which of the following show positive deviation from Raoult’s law?

Carbon disulphide and Acetone;

Phenol and Aniline;

Ethanol and Acetone

Correct Answer: Carbon disulphide and Acetone
View Solution

Question 50:

(c) The vapour pressure of a solution of glucose in water is 750 mm Hg at 100°C. Calculate the mole fraction of solute.

(Vapour pressure of water at 373 K = 760 mm Hg)

Correct Answer: Mole fraction of glucose (solute) = 0.0132
View Solution

Question 51:

The boiling point of solution increases when 1 mol of NaCl is added to 1 litre of water while addition of 1 mol of methanol to one litre of water decreases its boiling point. Explain the above observations.

Correct Answer: NaCl raises boiling point due to non-volatile nature; methanol lowers boiling point due to volatile nature and positive deviation.
View Solution

Question 52:

(i) A cell and its emf is given below:

Pt (s) \(\mid\) H\(_2\)(g, 1 bar) \(\mid\) H\(^+\)(aq, 1 M) \(\parallel\) Cu\(^{2+}\)(aq, 1 M) \(\mid\) Cu (s)

emf of the cell = +0.34 V

Write the reduction half-reaction at cathode.

Correct Answer: Cu\(^{2+}\)(aq) + 2e\(^-\) → Cu(s)
View Solution

Question 53:

How is standard Gibbs energy for a reaction related to equilibrium constant?

Correct Answer: \(\Delta G^\circ = -RT \ln K\)
View Solution

Question 54:

Calculate emf of the given cell:

Mg(s) \(\mid\) Mg\(^{2+}\)(0.1 M) \(\parallel\) Cu\(^{2+}\)(1.0 × 10\(^{-3}\) M) \(\mid\) Cu(s)


Given:
\(E^\circ_{Cu^{2+}/Cu} = +0.34\) V, \quad \(E^\circ_{Mg^{2+}/Mg} = -2.37\) V

(log 100 = 2)

Correct Answer: E\(_{\text{cell}}\) = 2.61 V
View Solution

Question 55:

State Kohlrausch’s law of independent migration of ions.

Correct Answer:
Kohlrausch’s law states that:
\textit{At infinite dilution, the molar conductivity of an electrolyte is equal to the sum of the individual contributions of the cation and anion.}
Mathematically:
\[\Lambda_m^\circ = \lambda^\circ_+ + \lambda^\circ_-\]
View Solution

Question 56:

How much electricity in terms of Faraday is required to produce 40 g of Al from molten Al\(_2\)O\(_3\)?

(Given: Atomic mass of Al = 27 u)

Correct Answer: \(4.44 \, \text{Faraday}\)
View Solution

Question 57:

Calculate log \(K_c\) for the following reaction at 298 K:

Zn(s) + Cu\(^{2+}\)(aq) \(\rightleftharpoons\) Zn\(^{2+}\)(aq) + Cu(s)


Given:
\(E^\circ_{Zn^{2+}/Zn} = -0.76 \, V\), \quad \(E^\circ_{Cu^{2+}/Cu} = +0.34 \, V\)

Correct Answer: \(\log K_c = 37.29\)
View Solution

Question 58:

(a) Compound A undergoes Rosenmund reduction to give compound B with molecular formula C\textsubscript{7}H\textsubscript{6}O. Compound B does not give Fehling’s test but reacts with conc. NaOH to give C and D.

Identify A, B, C and D and write all the reactions involved.

Write one chemical test to distinguish between compound B and propanone.

Correct Answer:
A = Benzoyl chloride (C\textsubscript{6}H\textsubscript{5}COCl)
B = Benzaldehyde (C\textsubscript{6}H\textsubscript{5}CHO)
C = Benzoic acid (C\textsubscript{6}H\textsubscript{5}COOH)
D = Benzyl alcohol (C\textsubscript{6}H\textsubscript{5}CH\textsubscript{2}OH)
View Solution

Question 59:

Compound A with molecular formula (C\textsubscript{2}H\textsubscript{6}O) on oxidation by PCC gives compound B, which on treatment with dilute alkali forms compound C (a β-hydroxy aldehyde). B on oxidation by potassium permanganate forms C.

Identify A, B, C and D and write all the chemical equations involved.

Correct Answer:
A = Ethanol (CH\textsubscript{3}CH\textsubscript{2}OH)
B = Acetaldehyde (CH\textsubscript{3}CHO)
C = 3-Hydroxybutanal (CH\textsubscript{3}CH(OH)CH\textsubscript{2}CHO)
D = Acetic acid (CH\textsubscript{3}COOH)
View Solution

Question 60:

The chemistry of the actinoids is more complex as compared to the lanthanoids. Why?

Correct Answer:
Actinoids exhibit more complex chemistry due to the greater number of oxidation states and greater tendency to form coordination compounds than lanthanoids.
View Solution

Question 61:

Why is E\textdegree{} for Mn\textsuperscript{3+}/Mn\textsuperscript{2+} redox couple more positive?

Correct Answer:
Because Mn\textsuperscript{3+} is unstable in aqueous solution and readily reduces to Mn\textsuperscript{2+}.
View Solution

Question 62:

Why do transition metals form large numbers of complex compounds?

Correct Answer:
Due to small size, high charge, and availability of vacant d-orbitals for bonding.
View Solution

Question 63:

How does acidified potassium permanganate solution react with Fe\textsuperscript{2+} ions? Write ionic equation.

Correct Answer:
\[ \text{MnO}_4^- + 8H^+ + 5Fe^{2+} \rightarrow Mn^{2+} + 5Fe^{3+} + 4H_2O \]
View Solution

Question 64:

Calculate the ‘spin only’ magnetic moment of a divalent ion of a metal M in aqueous solution. The atomic number of the metal M is 25.

Correct Answer: \( \mu = \sqrt{n(n+2)} = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \, \text{BM} \)
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