CBSE Class 12 Punjabi Question Paper 2022 with Answer Key (May 11)

CBSE CLASS XII Questions

• 1.

  Which of the following is not related to positive attitude?

  • It makes a person happier.
    
  • It helps to build and maintain relationships.
    
  • It decreases one's chances of success.
    
  • It helps to make better decisions.
    
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• 2.

  Arrange the following historical events in chronological order and choose the correct option: I. Champaran Satyagraha
  II. Kheda Satyagraha
  III. Jallianwala Bagh Incident
  IV. Rowlatt Act
  Options:

  • I, II, III, IV
    
  • I, II, IV, III
    
  • II, III, I, IV
    
  • II, IV, III, I
    
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• 3.

  There are two statements Assertion (A) and Reason (R):
  Assertion (A): At the time of admission of a new partner in a partnership firm, the newly admitted partner brings an agreed amount of capital either in cash or in kind.
  Reason (R): On admission, the new partner gets the right to acquire share in the assets and profits of the partnership firm.
  Choose the correct option from the following:

  • Both Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A).
    
  • Both Assertion (A) and Reason (R) are correct, but Reason (R) is not the correct explanation of Assertion (A).
    
  • Assertion (A) is correct, but Reason (R) is incorrect.
    
  • Assertion (A) is incorrect, but Reason (R) is correct.
    
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• 4.

  From the following information obtained from the books of 'Ajanta Ltd.', calculate Cash from Operations: Net Profit for the year ended 31st March, 2025 after charging depreciation of ₹ 80,000 and after writing off goodwill ₹ 10,500 was ₹ 4,90,000. Additional Information:

  

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• 5.

  Calculate emf of the following cell at 298 K: \[ \text{Cr(s)} \, | \, \text{Cr}^{3+} (aq) \, (0.1\, M) \; || \; \text{Fe}^{2+} (aq) \, (0.01\, M) \, | \, \text{Fe(s)} \] Given: \[ E^\circ_{\text{Cr}^{3+}/\text{Cr}} = -0.74 \, V, \quad E^\circ_{\text{Fe}^{2+}/\text{Fe}} = -0.44 \, V, \quad \log 10 = 1 \]

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• 6.

  The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

  • \( \dfrac{3h}{2\pi} \)
    
  • \( \dfrac{2h}{\pi} \)
    
  • \( \dfrac{h}{\pi} \)
    
  • \( \dfrac{h}{2\pi} \)
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