An electric current of 3 A flows via a wire of resistance 15 ohms. How much heat will be produced in a minute?

As per the given data,

Current via resistance, I = 3 A.
The value of the resistance, R = 15 Ω.
Time required for heat development = t = 60 seconds

Step 1: Joule’s Law of Heating

Joule's law says that when current I flows in a conductor of resistance R for time T sec, then the generated heat on the conductor is directly proportional to the square of the electric current.
Joule's law of heating can be expressed by H = I²RT (Q = generated heat on the conductor).

Step 2: Heat Calculation

In order to determine the given question, we need to apply Joule’s Law,

H = I²RT = 3² \(\times\) 15 \(\times\) 60

Thus, H = 8100 Joule

Hence, 8100 Joule heat will be produced in a minute.

Also Check: NCERT Solutions for Class 6 to 12

Related Questions

Read More:

Important Topics of Resistance
Conductivity	Unit of Specific Resistance	Ampere
Cells, emf, Internal Resistance	Current Electricity	Electric Dipole
Combination of Resistors	Current density	Derivation of Drift Velocity
Cells in Series and in Parallel	Power transformers	Resistivity Temperature Dependence
Types of Resistors	Difference between air conditioning and refrigeration	Potentiometer
Permittivity And Permeability	Wheatstone Bridge	Resistor Colour Codes
Power of Alternating Current	Difference between RTD and thermocouple	Difference between AC and DC
Ohm’s Law and its Limitations	Relation between resistance and length	Resistivity formula
Static Electricity	Unit of Current	Voltage
Ohm’s law	Difference between kva and kw	Types of Current
Current density formula	Difference between earth and neutral	Electrical Formula
Relation between kva and kw	Difference Between Primary Cell and Secondary Cell	Electromotive Force
Resistance Formula	Internal resistance formula	Difference between emf and voltage
Carbon Resistor	Differences Between Acceleration and Velocity	Relation between power and resistance
Uses of Resistor	Current Electricity MCQ	Drift Velocity

CBSE CLASS XII Related Questions

1.
The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

\( 0.5 \times 10^3 \, \text{m}^{-1} \)
\( 6.0 \times 10^2 \, \text{m}^{-1} \)
\( 7.5 \times 10^2 \, \text{m}^{-1} \)
\( 1.5 \times 10^3 \, \text{m}^{-1} \)

View Solution

2.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

attract with a force \( \frac{F}{2} \)
repel with a force \( \frac{F}{2} \)
repel with a force \( F \)
attract with a force \( F \)

View Solution

3.
The electric potential (V ) and electric field (⃗ E) are closely related concepts in electrostatics. The electric field is a vector quantity that represents the

Production of AC is economical.
AC can be easily and efficiently converted from one voltage to another.
AC can be transmitted economically over long distances.
AC is less dangerous.

View Solution

4.
Four long straight thin wires are held vertically at the corners A, B, C and D of a square of side \( a \), kept on a table and carry equal current \( I \). The wire at A carries current in upward direction whereas the current in the remaining wires flows in downward direction. The net magnetic field at the centre of the square will have the magnitude:

\( \dfrac{\mu_0 I}{\pi a} \) and directed along OC
\( \dfrac{\mu_0 I}{\pi a \sqrt{2}} \) and directed along OD
\( \dfrac{\mu_0 I \sqrt{2}}{\pi a} \) and directed along OB
\( \dfrac{2\mu_0 I}{\pi a} \) and directed along OA

View Solution

5.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

5 V
3.5 V
2.5 V
Zero V

View Solution

6.
A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
the magnetic dipole moment of the coil, and
the magnitude of the counter torque that must be applied to prevent the coil from turning.

View Solution

An electric current of 3 A flows via a wire of resistance 15 ohms. How much heat will be produced in a minute?

Step 1: Joule’s Law of Heating

Step 2: Heat Calculation

Related Questions

CBSE CLASS XII Related Questions

1.
The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

2.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

3.
The electric potential (V ) and electric field (⃗ E) are closely related concepts in electrostatics. The electric field is a vector quantity that represents the

5.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

An electric current of 3 A flows via a wire of resistance 15 ohms. How much heat will be produced in a minute?

Step 1: Joule’s Law of Heating

Step 2: Heat Calculation

Related Questions

CBSE CLASS XII Related Questions

1.The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

2.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

3.The electric potential (V ) and electric field (⃗ E) are closely related concepts in electrostatics. The electric field is a vector quantity that represents the

5.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

2.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

3.
The electric potential (V ) and electric field (⃗ E) are closely related concepts in electrostatics. The electric field is a vector quantity that represents the

5.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be: