Latus Rectum of Parabola: Formula, Length & Derivation

Collegedunia Team logo

Collegedunia Team

Content Curator

Latus rectum of a parabola is the line passing through its foci which is parallel to the directrix of the parabola and perpendicular to the axis of the parabola. A parabola has only one latus rectum whereas an ellipse and a hyperbola have 2 latus rectums. 

Length of Latus Rectum of a Parabola LL’ = 4a

The focus of the parabola lies exactly at the midpoint of the length of the latus rectum and they are all collinear in nature. For a parabola, the length of the Latus Rectum is 4 times the distance between the focus and the vertex.

Key Terms : Parabola, Latus Rectum, Derivation of Length, vertex, Hyperbola


What is a Parabola?

[Click Here for Sample Questions]

Parabola is the locus of a point that moves in a plane, such that its distance from a fixed point is equal to its perpendicular distance from a fixed straight line. There are four standard equations of a parabola as follows:

  • y2 = 4ax
  • y2 = – 4ax
  • x2 = 4ay
  • x2 = – 4ay
Parabola

Parabola

The important formulas relating to the Latus Rectum of a parabola are tabulated below.

Parabola Vertex Focus Axis of Symmetry Directrix Length of Latus Rectum Endpoints of Latus Rectum
y2 = 4ax (0,0) (a,0) y = 0 x = -a 4a (a,±2a)
y2 = – 4ax (0,0) (-a,0) y = 0 x = a 4a (-a,±2a)
x2 = 4ay (0,0) (0,a) x = 0 y = -a 4a (±2a,a)
x2 = – 4ay (0,0) (0,-a) x = 0 y = a 4a (±2a,-a)

Discover about the Chapter video:

Conic Sections Detailed Video Explanation:


Latus Rectum of a Parabola

[Click Here for Sample Questions]

Latus rectum of a conic section is a chord that is parallel to the directrix and passes through the focus. The half-length of the Latus Rectum is called Semi-Latus Rectum. The Latus Rectum of a parabola is a line segment perpendicular to the axis of the parabola, which passes through the focus and whose endpoints lie on the parabola. 

The length of the latest rectum is denoted by 4a

where a is the distance between the vertex and the focus of the parabola. 

The half-length of the Latus Rectum is called Semi-Latus Rectum and it is denoted by 2a

The endpoints of the Latus Rectum lie on the parabola, which is denoted as L(a,2a) and L’(a,-2a).

Latus Rectum of a Parabola

Latus Rectum of a Parabola

Two parabolas are said to be equal if they have the Latus Rectum of the same length.

Also Read: Latus Rectum of Ellipse


Derivation of Length of the Latus Rectum

[Click Here for Sample Questions]

We know that the endpoints on the Latus Rectum are L(a,2a) and L’(a,-2a). Hence, to find the length of the Latus Rectum, all we have to do is find the distance between the points L and L’.

 Using Distance Formula, the length LL’ is 

\(\to\) \(\sqrt{[(a - a)² + {2a - (-2a)}²]} \)

\(\to\)[0 + {2a + 2a}2]

\(\to\)[4a2]

\(\to ±\)4a

As the distance cannot be negative, we get the length of the Latus Rectum as 4a.


Things to Remember

[Click Here for Sample Questions]

  • Latus rectum of a parabola is the line passing through its foci which is parallel to the directrix of the parabola.
  • Length of Latus Rectum of a Parabola LL’ = 4a.
  • For a parabola, the length of the Latus Rectum is 4 times the distance between the focus and the vertex.
  • The end points of the latus rectum of a parabola with standard equation y² = 4ax is (a,±2a)

Sample Questions

Ques. Find the equation of the parabola with vertex at (0, 0) and focus at (0, 2). [2 marks]

Ans: Since the vertex is at (0,0) and the focus is at (0,2) which lies on the y-axis, the y-axis is the axis of the parabola. Therefore, the equation of the parabola is of the form x² = 4ay. Thus, we have, 

x2 = 4(2)y 

i.e., x2 = 8y 

Ques. Find the length of the latus rectum of the parabola y2 - 2y = -2x - 3. [2 marks]

Ans: y2 - 2y = -2x - 3

(y - 1)2 - 1 = -2x - 3

(y - 1)2 = -2x - 3 + 1

(y - 1)2 = -2x - 2

(y - 1)2 = -2(x + 1)

Therefore, the length of the Latus Rectum is 2.

Ques. For parabola y2=84x, what are the endpoints and length of the Latus Rectum? [2 marks]

Ans: The standard equation of the parabola is 

y2=4ax

Comparing it with y2=84x, we get

4ax = 84x

4a = 84

a = 21

We know that the endpoints on the Latus Rectum are L(a,2a) and L’(a,-2a).

Therefore, the endpoints are L(21,42) and L’(21,-42).

Also, the length of the Latus Rectum is 84.

Ques. For parabola y²=96x, what are the endpoints and length of the Latus Rectum? [2 marks]

Ans: The standard equation of the parabola is 

y2=4ax

Comparing it with y2=96x, we get

4ax = 96x

4a = 96

a = 24

We know that the endpoints on the Latus Rectum are L(a,2a) and L’(a,-2a).

Therefore, the endpoints are L(24,48) and L’(24,-48).

Also, the length of the Latus Rectum is 96.

Ques. For parabola y2=-24x, what are the endpoints and length of the Latus Rectum? [2 marks]

Ans: The standard equation of the parabola is 

y2=-4ax

Comparing it with y2=-24x, we get

4ax = 24x

4a = 24

a = 6

We know that the endpoints on the Latus Rectum are L(-a,2a) and L’(-a,-2a).

Therefore, the endpoints are L(-6,12) and L’(-6,-12).

Also, the length of the Latus Rectum is 24.

Ques. For parabola x2= – 36y, what are the endpoints and length of the Latus Rectum? [2 marks]

Ans: The standard equation of the parabola is 

x2=-4ay

Comparing it with x2=-36y, we get

4ay = 36y

4a = 36

a = 9

We know that the endpoints on the Latus Rectum are L(2a, -a) and L’(-2a, -a).

Therefore, the endpoints are L(18,-9) and L’(-18,-9).

Also, the length of the Latus Rectum is 36.

Ques. For parabola x2=-72y, what are the endpoints and length of the Latus Rectum? [2 marks]

Ans: The standard equation of the parabola is 

x2=-4ay

Comparing it with x2=-72y, we get

4ay = 72y

4a = 72

a = 18

We know that the endpoints on the Latus Rectum are L(2a, -a) and L’(-2a, -a).

Therefore, the endpoints are L(36,-18) and L’(-36,-18).

Also, the length of the Latus Rectum is 72.

Ques. For parabola x2=64y, what are the endpoints and length of the Latus Rectum? [2 marks]

Ans: The standard equation of the parabola is 

x2=4ay

Comparing it with x²=64y, we get

4ay = 64y

4a = 64

a = 16

We know that the endpoints on the Latus Rectum are L(2a, a) and L’(-2a, a).

Therefore, the endpoints are L(32,16) and L’(-32,16).

Also, the length of the Latus Rectum is 64.


Also Read:

Related Links:

CBSE CLASS XII Related Questions

  • 1.
    Evaluate : \[ \int_{\frac{1}{12}}^{\frac{5}{12}} \frac{dx}{1+\sqrt{\cot x}} \]


      • 2.

        A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 

        (i) Express \(y\) as a function of \(x\) from the given equation of ellipse. 
        (ii) Integrate the function obtained in (i) with respect to \(x\). 
        (iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration. 
        OR 
        (iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\). 
         


          • 3.
            A line passing through the points \(A(1,2,3)\) and \(B(6,8,11)\) intersects the line \[ \vec r = 4\hat i + \hat j + \lambda(6\hat i + 2\hat j + \hat k) \] Find the coordinates of the point of intersection. Hence write the equation of a line passing through the point of intersection and perpendicular to both the lines.


              • 4.
                Find : \[ \int \frac{2x+1}{\sqrt{x^2+6x}}\,dx \]


                  • 5.

                    Smoking increases the risk of lung problems. A study revealed that 170 in 1000 males who smoke develop lung complications, while 120 out of 1000 females who smoke develop lung related problems. In a colony, 50 people were found to be smokers of which 30 are males. A person is selected at random from these 50 people and tested for lung related problems. Based on the given information answer the following questions: 

                    (i) What is the probability that selected person is a female? 
                    (ii) If a male person is selected, what is the probability that he will not be suffering from lung problems? 
                    (iii)(a) A person selected at random is detected with lung complications. Find the probability that selected person is a female. 
                    OR 
                    (iii)(b) A person selected at random is not having lung problems. Find the probability that the person is a male. 
                     


                      • 6.
                        Find the general solution of the differential equation \[ y\log y\,\frac{dx}{dy}+x=\frac{2}{y}. \]

                          CBSE CLASS XII Previous Year Papers

                          Comments


                          No Comments To Show