NCERT Solutions for class 10 Mathematics Chapter 11: Constructions

NCERT Solutions for Class 10 Mathematics Chapter 11 Constructions are provided in this article. Some of the important topics in Constructions chapter include:

Expected no of questions: 1 to 2 questions of total 4 marks

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NCERT Solutions for Class 10 Mathematics Chapter 11

NCERT Solutions for Class 10 Mathematics Chapter 11 Constructions is given below.

NCERT Solutions

Class 10 Mathematics Chapter 11 Constructions – Important Topics

Construction here in geometry means drawing geometrical figures such as shapes like circles, lines with the help of a compass or a ruler/scale. Note: You cannot measure angles using a protractor, or measure lengths with a ruler for constructions.

Some of the construction techniques covered in this chapter include:

Bisection of a Line Segment
Division of a Line Segment in the ratio m:n
Construction of Triangle with a scale factor m:n
Construction of Tangent to the Circle from a Point Outside the Circle
Construction of Tangent to the Circle from a Point on the Circle

NCERT Solutions for Class 10 Chapter 11 Exercises

NCERT Solutions for Class 10 Chapter 11 Constructions Exercises is given below.

Chapter Related Articles:

Line Segment	Line and ray	Equilateral Triangle
Scalene Triangle	Division Line Segments	Constructions MCQs
Formula of Perimeter Shapes	Area and Volume	Properties of Triangle

Maths Related Articles:

NCERT Solutions for Class 10 Mathematics	Important Maths Formulas	Maths Study material
Difference between in Maths	Algebra	Arithmetics
Geometry	Number System	Mensuration

CBSE X Related Questions

1.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is
- \(2\pi r^3\)
- \(3\pi r^3\)
- \(5\pi r^3\)
- \(4\pi r^3\)
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2.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.
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3.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
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4.
PQ is tangent to a circle with centre O. If \(OQ = a\), \(OP = a + 2\) and \(PQ = 2b\), then relation between \(a\) and \(b\) is
- \(a^2 + (a + 2)^2 = (2b)^2\)
- \(b^2 = a + 4\)
- \(2a^2 + 1 = b^2\)
- \(b^2 = a + 1\)
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5.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.
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6.
A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))
- \(314 \sqrt{2}\) \(\text{cm}^{2}\)
- \(314\) \(\text{cm}^{2}\)
- \(\frac{3140}{3}\) \(\text{cm}^{2}\)
- \(3140 \sqrt{2}\) \(\text{cm}^{2}\)
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