NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

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NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Exercise 12.2 Solutions are based on the Perimeter And Area Of A Circle.

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Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

Also check other Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.1 Solutions

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.3 Solutions

Also Check:

Chapter Related Topics
Circumference of Circle	Areas Related to Circles Formula	Areas Related to Circles Revision Notes
Area of Sector	Sector Of A Circle	Area of Segment of a Circle
Circle Formula	Area of a Circle Formula	Arc Length Formula
Mathematics diameter formula	Central Angle of a Circle Formula	Radius of a Circle

Also Check:

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CBSE X Related Questions

1.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.
View Solution
2.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.
View Solution
3.
An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals
- \(1 : 8\)
- \(1 : 2\)
- \(1 : 1\)
- \(2 : 1\)
View Solution
4.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is
- \(2\pi r^3\)
- \(3\pi r^3\)
- \(5\pi r^3\)
- \(4\pi r^3\)
View Solution
5.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is
- \(10^{\circ}\)
- \(60^{\circ}\)
- \(45^{\circ}\)
- \(100^{\circ}\)
View Solution
6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution

View All

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NCERT Solutions For Class 10 mathematics Chapter 12: Areas Related to Circles

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You can also check

NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

2.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

3.
An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals

4.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

5.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

2.Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

3.An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals

4.Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

5.Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

6.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

2.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

3.
An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals

4.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

5.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is