CAT 2023 Slot 2 DILR Question Paper is available here for free download. CAT 2023 Slot 2 paper has been conducted on November 26 from 12.30 PM to 2.30 PM. CAT 2023 Slot 2 question paper DILR comprises 20 questions to be attempted in 40 minutes. According to initial students reaction, CAT 2023 Slot 2 DILR was moderate to difficult.

CAT 2023 Slot 2 DILR Question Paper with Solutions PDF

CAT 2023 DILR Question Paper PDF CAT 2023 DILR Answer Key PDF CAT 2023 DILR Solution PDF

CAT 2023 Slot 2 DILR Questions with Solution

Question Question Details Correct Answer Solution
1 For which firm(s) can the amounts raised by them be concluded with certainty in each year?
Options:
1. Only Czechy
2. Only Bzygoo and Czechy and Drjbna
3. Only Drjbna
4. Only Czechy and Drjbna
4 Based on the conditions, Czechy raised Rs. 1 crore in 2013 and 2016, with a total of Rs. 9 crores over 4 years. A feasible pattern that satisfies all conditions is 1 → 3 → 4 → 1. Similarly, Drjbna raised Rs. 1 crore in 2011 and 2015 with a total of Rs. 10 crores over 5 years. The pattern 1 → 3 → 2 → 3 → 1 meets all constraints. Therefore, amounts raised each year can be determined for both Czechy and Drjbna.
2 What best can be concluded about the total amount of money raised in 2015?
Options:
1. It is either Rs. 7 crores or Rs. 8 crores or Rs. 9 crores.
2. It is either Rs. 7 crores or Rs. 8 crores.
3. It is exactly Rs. 8 crores.
4. It is either Rs. 8 crores or Rs. 9 crores.
2 In 2015, only Drjbna and Bzygoo were active, and based on the conditions, their contributions would range between Rs. 7 and Rs. 8 crores. This analysis aligns with the constraints, leading to the conclusion that the amount raised in 2015 is either Rs. 7 crores or Rs. 8 crores.
3 What is the largest possible total amount of money (in Rs. crores) that could have been raised in 2013? 17 In 2013, Alfloo, Czechy, and Elavalaki were active. By applying the constraints, maximizing the possible amount each firm could raise in 2013, and ensuring each firm’s amount complies with the conditions, the maximum possible total raised in 2013 is Rs. 17 crores.
4 If Elavalaki raised Rs. 3 crores in 2013, then what is the smallest possible total amount of money (in Rs. crores) that could have been raised by all companies in 2012?
Options:
1. 10
2. 9
3. 12
4. 11
4 Starting from Elavalaki raising Rs. 3 crores in 2013, and then analyzing previous years, the smallest possible total amount for 2012 is calculated as Rs. 11 crores, keeping within the constraints of each firm’s increase and decrease pattern.
5 If the total amount of money raised in 2014 is Rs. 12 crores, then which of the following is not possible?
Options:
1. Alfloo raised the same amount of money as Drjbna in 2013.
2. Bzygoo raised more money than Elavalaki in 2014.
3. Bzygoo raised the same amount of money as Elavalaki in 2013.
4. Alfloo raised the same amount of money as Bzygoo in 2014.
3 Analyzing each option, the yearly increment and decrement constraints show that Bzygoo cannot have raised the same amount as Elavalaki in 2013 without violating the conditions. Thus, Option 3 is not possible.
6 What was the total amount spent on tickets (in Rs.) by Bipasha?
Options:
1. 110
2. 100
3. 90
4. 120
1 By matching ticket prices and Bipasha's ride sequence (Ride 2 at 11:30 am for Rs. 50, followed by Ride 4 for Rs. 40, and Ride 1 for Rs. 20), her total expenses add up to Rs. 110.
7 Which were all the rides that Anjali completed by 2:00 pm?
Options:
1. Ride-1 and Ride-3
2. Ride-1, Ride-2, and Ride-4
3. Ride-1 and Ride-4
4. Ride-1, Ride-2, and Ride-3
4 Following Anjali's schedule, Ride-1 was taken at 11 am, with Ride-2 and Ride-3 completed by 2:00 pm. Thus, the correct answer is Ride-1, Ride-2, and Ride-3.
8 Which ride was taken by all three visitors?
Options:
1. Ride-1
2. Ride-3
3. Ride-2
4. Ride-4
1 All three visitors took Ride-1. Chitra took Ride-2 only, while Anjali took Ride-1, and Bipasha took Ride-1 as her last ride. Therefore, Ride-1 was taken by all three.
9 How many rides did Anjali and Chitra take in total? 6 Chitra took 2 rides, while Anjali took 4, as per the schedule. Together, they completed a total of 6 rides.
10 What was the total amount spent on tickets (in Rs.) by Anjali? 140 Analyzing Anjali’s rides (Ride-1 for Rs. 20, Ride-2 for Rs. 50, Ride-3 for Rs. 30, and Ride-4 for Rs. 40), her total ticket expenditure is Rs. 140.
11 What is Akhil’s score on Day 1?
Options:
1. 7
2. 6
3. 5
4. 8
1 Given that Akhil ranked 1st on Day 1, his score must be higher than Bimal’s (5) and Chatur’s (3). Therefore, Akhil’s score on Day 1 is 7.
12 Who attains the maximum total score?
Options:
1. Bimal
2. Chatur
3. Cannot be determined
4. Akhil
2 Based on Chatur’s unique high scores, including a peak score on Day 2, he is likely to achieve the maximum total score over five days.
13 What is the minimum possible total score of Bimal? 25 Assigning minimum possible values for Bimal based on rankings and constraints (e.g., Day 1 and Day 3 scores as 5), Bimal’s minimum total score is calculated as 25.
14 If the total score of Bimal is a multiple of 3, what is the score of Akhil on Day 2?
Options:
1. Cannot be determined
2. 5
3. 6
4. 4
4 Considering Bimal’s total as a multiple of 3 and rank constraints, assigning 4 as Akhil’s score on Day 2 satisfies all conditions.
15 If Akhil attains a total score of 24, then what is the total score of Bimal? 26 Using total score constraints and 2-day averages, Bimal’s score is calculated as 26 to satisfy all conditions with Akhil’s total score of 24.
16 What is the total number of coins in all the boxes in the 3rd row?
Options:
1. 36
2. 30
3. 15
4. 45
4 Using row and column total constraints and distinct averages, the total number of coins in the 3rd row sums to 45.
17 How many boxes have at least one sack containing 9 coins?
Options:
1. 3
2. 8
3. 5
4. 4
3 Based on Table 2’s “**” notation, which indicates multiple conditions (including having a sack with 9 coins), 5 boxes meet this criterion.
18 For how many boxes are the average and median of the numbers of coins contained in the three sacks in that box the same? 4 Boxes where the average and median match can be identified based on balanced or symmetrical values. Four boxes meet this condition.
19 How many sacks have exactly one coin? 9 Analyzing Table 2 and condition (i), nine sacks across different boxes contain exactly one coin.
20 In how many boxes do all three sacks contain different numbers of coins? 5 Boxes with distinct sack values are identified from Tables 1 and 2. Five boxes have sacks with different numbers of coins.