NCERT Solutions for Class 10 Maths Chapter 6: Triangles

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The NCERT Solutions for class 10 maths chapter 6 Triangles are provided in the article below. A triangle is a polygon having three sides and three angles. Based on whether they have equal sides or not, triangles can be categorised as equilateral, isosceles and scalene triangles.

Chapter 6 Triangles is included in the class 10 syllabus 2022-23 under the Unit Geometry. This unit carries a weightage of 15 Marks in class 10 mathematics board exam. Chapter 10 Circles is also a part of this unit. The important topics from this chapter includes similarity of triangles, congruence of triangles and pythagoras theorem.

NCERT Solutions for Class 10 Maths Chapter 6

Class 10 Maths Chapter 6 Triangles: Important Topics

Some important concepts of chapter 6 Triangles are given below:

Similarity of Triangles – Two triangles are said to be similar if their corresponding angles are equal and their corresponding sides are in the same ratio. Triangles with equal corresponding angles are called equiangular triangles.

Basic Proportionality Theorem states that the ratio of any two corresponding sides in two equiangular triangles is always the same.

Congruence of Triangles – Two triangles are said to be congruent if all their corresponding sides and angles are equal in measure.

Congruent triangles always satisfy any of the given conditions:

SSS (Side-Side-Side) Rule, SAS (Side-Angle-Side) Rule, ASA (Angle-Side-Angle) Rule, AAS (Angle-Angle-Side Rule), RHS (Right angle-Hypotenuse-Side) Rule.

Pythagoras Theorem – It states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of squares of other two sides.

Pythagoras theorem can be represented as (H)² = (P)² + (B)², where H is Hypotenuse, P is perpendicular and B is Base.

NCERT Solutions for Class 10 Maths Chapter 6 Exercises:

The NCERT solutions of all the exercises of class 10 maths chapter 6 Triangles are given below:

Read Also:

Triangles Important Questions	Triangles Revision Notes	MCQ on Triangles
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Algebra	Mensuration Formula	Geometry
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CBSE X Related Questions

1.
Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.
View Solution
2.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
3.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.
View Solution
4.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.
View Solution
5.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is
- \(2\pi r^3\)
- \(3\pi r^3\)
- \(5\pi r^3\)
- \(4\pi r^3\)
View Solution
6.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is
- \(10^{\circ}\)
- \(60^{\circ}\)
- \(45^{\circ}\)
- \(100^{\circ}\)
View Solution

View All

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NCERT Solutions for Class 10 Maths Chapter 6: Triangles

NCERT Solutions for Class 10 Maths Chapter 6

Class 10 Maths Chapter 6 Triangles: Important Topics

NCERT Solutions for Class 10 Maths Chapter 6 Exercises:

CBSE X Related Questions

1.
Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.

2.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

3.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

4.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

5.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

6.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 10 Maths Chapter 6: Triangles

NCERT Solutions for Class 10 Maths Chapter 6

Class 10 Maths Chapter 6 Triangles: Important Topics

NCERT Solutions for Class 10 Maths Chapter 6 Exercises:

CBSE X Related Questions

1.Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.

2.Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5. Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

3.Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

4.A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

5.Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

6.Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.

2.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

3.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

4.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

5.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

6.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is