NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.4

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.4 are provided in this article. Class 10 Maths Chapter 6 Triangles is an important chapter included under the Unit Geometry of class 10 maths syllabus. This chapter covers important concepts related to triangles. Exercise 6.4 mainly includes questions based on areas of similar triangles.

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.4

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Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:


Class 10 Chapter 6 Triangles Related Links:

Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

      • \(2\pi r^3\)
      • \(3\pi r^3\)
      • \(5\pi r^3\)
      • \(4\pi r^3\)

    • 2.
      Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
      Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

        • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
        • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
        • Assertion (A) is true, but Reason (R) is false.
        • Assertion (A) is false, but Reason (R) is true.

      • 3.
        Assertion (A) : \((\sqrt{3} + \sqrt{5})\) is an irrational number.
        Reason (R) : Sum of the any two irrational numbers is always irrational.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Assertion (A) is false, but Reason (R) is true.

        • 4.
          An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals

            • \(1 : 8\)
            • \(1 : 2\)
            • \(1 : 1\)
            • \(2 : 1\)

          • 5.
            Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)


              • 6.
                Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

                  • \(10^{\circ}\)
                  • \(60^{\circ}\)
                  • \(45^{\circ}\)
                  • \(100^{\circ}\)

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