NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.1

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NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Exercise 3.1 is provided in this article. Class 10 Maths Chapter 3 Exercise 3.1 has 3 questions regarding the representation of the given form of equations algebraically or graph of the linear equations.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 3 Pair of Linear Equations in Two Variables Exercise 3.1

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Class 10 Chapter 3 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals

      • \(1 : 8\)
      • \(1 : 2\)
      • \(1 : 1\)
      • \(2 : 1\)

    • 2.
      Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.


        • 3.
          Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

            • \(2\pi r^3\)
            • \(3\pi r^3\)
            • \(5\pi r^3\)
            • \(4\pi r^3\)

          • 4.
            For any natural number n, \( 5^n \) ends with the digit :

              • 0
              • 5
              • 3
              • 2

            • 5.
              Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

                • \(10^{\circ}\)
                • \(60^{\circ}\)
                • \(45^{\circ}\)
                • \(100^{\circ}\)

              • 6.
                Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)

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