NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.2

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NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Exercise 3.2 consists of 7 questions. Class 10 Maths Chapter 3 Exercise 3.2 has questions related to the concepts of graph of linear equations and consistency and inconsistency of the equations.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 3 Pair of Linear Equations in Two Variables Exercise 3.2

Check out other exercise solutions of Class 10 Maths Chapter 3

Class 10 Chapter 3 Topics:

Pair of Linear Equations in Two Variables Important Questions	Pair of Linear Equations in Two Variables Formula	Pair of Linear Equations in Two Variables Revision Notes
Difference between linear and non-linear equations	Substitution Method	Cross-multiplication of solving linear equations

CBSE Class 10 Maths Study Guides:

Calculus	Mensuration	Arithmetic
Difference between in Maths	NCERT Solutions for Class 10 Maths	Math MCQs
Trigonometry	Math Study Notes	Math Formula

CBSE X Related Questions

1.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.
View Solution
2.
The dimensions of a window are 156 cm \(\times\) 216 cm. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.
View Solution
3.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is
- \(10^{\circ}\)
- \(60^{\circ}\)
- \(45^{\circ}\)
- \(100^{\circ}\)
View Solution
4.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution
5.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
6.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is
- \(2\pi r^3\)
- \(3\pi r^3\)
- \(5\pi r^3\)
- \(4\pi r^3\)
View Solution

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Similar Mathematics Concepts

Pair of Linear Equations In Two Variables Important Questions

Pair of Linear Equations in Two Variables: Revision Notes

Pair of Linear Equations in Two Variables Formula: Intersecting and Coincident Lines

NCERT Solutions for class 10 Maths Chapter 3: Pair Of Linear Equations In Two Variables

NCERT Solutions for Class 10 Maths: Chapter-wise Solutions and Important Topics

Pair of Linear Equations in Two Variables MCQs

NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.1

NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.3

NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.4

NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.5

CBSE X Syllabus

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NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.2

CBSE X Related Questions

1.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

2.
The dimensions of a window are 156 cm \(\times\) 216 cm. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

3.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

4.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

5.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

6.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.2

CBSE X Related Questions

1.Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

2.The dimensions of a window are 156 cm \(\times\) 216 cm. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

3.Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

4.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

5.Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5. Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

6.Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.

2.
The dimensions of a window are 156 cm \(\times\) 216 cm. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

3.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

4.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

5.
Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

6.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is