NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry is included under Unit 5 Trigonometry of class 10 maths syllabus. Chapter 8 exercise 8.2 covers important questions based on trigonometric ratios of some specific angles.

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Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

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CBSE X Related Questions

  • 1.
    Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

      • \(2\pi r^3\)
      • \(3\pi r^3\)
      • \(5\pi r^3\)
      • \(4\pi r^3\)

    • 2.
      Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.


        • 3.
          Assertion (A) : \((\sqrt{3} + \sqrt{5})\) is an irrational number.
          Reason (R) : Sum of the any two irrational numbers is always irrational.

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Assertion (A) is false, but Reason (R) is true.

          • 4.
            For any natural number n, \( 5^n \) ends with the digit :

              • 0
              • 5
              • 3
              • 2

            • 5.
              The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

                • 0
                • 1
                • 3
                • 2

              • 6.
                A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))

                  • \(314 \sqrt{2}\) \(\text{cm}^{2}\)
                  • \(314\) \(\text{cm}^{2}\)
                  • \(\frac{3140}{3}\) \(\text{cm}^{2}\)
                  • \(3140 \sqrt{2}\) \(\text{cm}^{2}\)

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