NCERT Solutions For Class 11 Physics Chapter 12: Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics are given in this article. Thermodynamics is a branch of physics that deals with the study of the transformation of heat energy into several other forms of energy. For example, when we rub our palms together, the work done in rubbing produces heat. This process of rubbing hands denotes a Thermodynamic process.

Class 11 Physics Chapter 12 Thermodynamics is of Unit 8 which has a weightage of 20 marks along with unit 7 and Unit 9. Class 11 NCERT Solutions for Chapter 12 cover important concepts of laws of thermodynamicsCarnot Cycle, Born Haber Cycleand Enthalpy.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 12


NCERT Solutions for Class 11 Physics Chapter 12

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Class 11 Physics Chapter 12 – Concepts Covered

  • Thermodynamics is the branch of physics that deals with the study of the transformation of heat into other forms of energy and vice-versa.
A collection of a large number of atoms or molecules confined within certain boundaries in a way that it has specific values of pressure (P), volume (V) and temperature (T) is known as a thermodynamic system.
  • Zeroth Law of Thermodynamics identifies thermal equilibrium and introduces the concept of temperature as a tool for identifying equilibrium. 
If two systems are in thermal equilibrium with a third system then those two systems themselves are in equilibrium with each other.
  • Work is said to be done if a system moves a certain distance in the direction of the applied force.
It is given as dW = PdV
where P refers to the pressure of the gas in the cylinder.

The total change in heat energy in any system is the sum of the work done and the change in internal energy.

  • Second Law of Thermodynamics is the principle that disallows certain phenomena that are consistent with the First law of thermodynamics.
The two statements of second law of thermodynamics are as follows – 
- Kelvin-Planck Statement: It is impossible to form an engine, operating in a cycle, to extract heat from a hot body and then convert it completely into work without leaving change anywhere i.e., 100% conversion of heat into work is not possible.
- Clausius Statement: It is impossible for a self acting machine, operating in a cycle, without the help of any external energy to transfer heat from a cold body to a hot body. Heat can not flow itself from a colder body to a hotter body.

CBSE CLASS XII Related Questions

  • 1.
    Light of which of the following colours will have the maximum energy in a photon associated with it?

      • Red light
      • Yellow light
      • Green light
      • Blue light

    • 2.
      Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

        • attract with a force \( \frac{F}{2} \)
        • repel with a force \( \frac{F}{2} \)
        • repel with a force \( F \)
        • attract with a force \( F \)

      • 3.
        Assertion : In Young’s double-slit experiment, the fringe width for dark and bright fringes is the same. Reason (R): Fringe width is given by \( \beta = \frac{\lambda D}{d} \), where symbols have their usual meanings.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Both Assertion (A) and Reason (R) are false.

        • 4.
          In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.


            • 5.
              A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
              the magnetic dipole moment of the coil, and
              the magnitude of the counter torque that must be applied to prevent the coil from turning.


                • 6.
                  Four long straight thin wires are held vertically at the corners A, B, C and D of a square of side \( a \), kept on a table and carry equal current \( I \). The wire at A carries current in upward direction whereas the current in the remaining wires flows in downward direction. The net magnetic field at the centre of the square will have the magnitude:

                    • \( \dfrac{\mu_0 I}{\pi a} \) and directed along OC
                    • \( \dfrac{\mu_0 I}{\pi a \sqrt{2}} \) and directed along OD
                    • \( \dfrac{\mu_0 I \sqrt{2}}{\pi a} \) and directed along OB
                    • \( \dfrac{2\mu_0 I}{\pi a} \) and directed along OA
                  CBSE CLASS XII Previous Year Papers

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