NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.2 Solutions are based on the concept of Surface area of a right circular cylinder.

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Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    For any natural number n, \( 5^n \) ends with the digit :

      • 0
      • 5
      • 3
      • 2

    • 2.
      Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.


        • 3.
          Assertion (A) : If probability of happening of an event is \(0.2p\), \(p>0\), then \(p\) can't be more than 5.
          Reason (R) : \(P(\bar{E}) = 1 - P(E)\) for an event \(E\).

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Assertion (A) is false, but Reason (R) is true.

          • 4.
            Prove that \(2 + 3\sqrt{5}\) is an irrational number given that \(\sqrt{5}\) is an irrational number.


              • 5.
                If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                  • \(4 \text{ cm}\)
                  • \(4\sqrt{2} \text{ cm}\)
                  • \(8 \text{ cm}\)
                  • \(2\sqrt{2} \text{ cm}\)

                • 6.
                  Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

                    • \(10^{\circ}\)
                    • \(60^{\circ}\)
                    • \(45^{\circ}\)
                    • \(100^{\circ}\)

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