NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.6 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.6 Solutions are based on the Volume of a cylinder.

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Check out NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.6 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.


      • 2.
        Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)


          • 3.
            The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

              • 0
              • 1
              • 3
              • 2

            • 4.
              If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                • \(4 \text{ cm}\)
                • \(4\sqrt{2} \text{ cm}\)
                • \(8 \text{ cm}\)
                • \(2\sqrt{2} \text{ cm}\)

              • 5.
                Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.


                  • 6.
                    Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

                      • \(10^{\circ}\)
                      • \(60^{\circ}\)
                      • \(45^{\circ}\)
                      • \(100^{\circ}\)

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