
Education Journalist | Study Abroad Strategy Lead
You might have heard about the depletion of the ozone layer. But do you know the compound responsible for the depletion of ozone layer is a haloalkane compound i.e. chlorofluorocarbon. These halogen compounds have many uses in our everyday life. For Example- chloroquine is used for the treatment of malaria, halothane is used as an anaesthetic during surgery, etc.
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Key Terms: Organic chemistry, hydrogen atom, reactions, Alkyl halides, chloroquine, Aliphatic hydrocarbon, halogen, atom, Chlorine, Iodine, Bromine, Fluorine
Haloalkanes or Alkyl Halides
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Haloalkanes or Alkyl Halides are formed by replacement of Hydrogen atom(s) in an Aliphatic hydrocarbon by halogen atom(s) like Chlorine, Iodine, Bromine and Fluorine.
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Haloarenes or Aryl Halides
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Haloarenes or Aryl Halides are formed by the replacement of Hydrogen atom(s) in an Aromatic hydrocarbon by halogen atom(s) like Chlorine, Iodine, Bromine and Fluorine.
Physical Properties of Haloalkanes and Haloarenes
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Physical properties depend upon mass of the compounds and the type of intermolecular and intramolecular forces of attraction. Both the Alkyl Halides and Aryl Halides have some physical properties that create the difference between them. Some of the properties are:
1. Physical State-
Haloalkanes are colourless in nature in their pure state. However, bromides and iodides develop colour on exposure to light due to which alkyl-bromide and alkyl-iodide have colour. The reason for the development of colour is that halogens get decomposed in the presence of light. Many of the halogen compounds having a volatile nature have a sweet smell.
Haloarenes are also colourless liquids or crystalline solids with a characteristic smell.
2. Boiling Point-
Boiling Point of a Molecule depends on the amount of energy provided in the form of heat or temperature to break the force of attraction between any two molecules in any state. The energy required to break this intermolecular force decides the level of Boiling of that molecule in its liquid state.
Therefore, we can say that
Boiling Point ∝ Intermolecular forces
There are two types of Intermolecular Forces:
(a) Hydrogen Bond (exists rarely) and
(b) Van der Waals Forces (exists generally): It exists between two molecules of alkyl halides ( R-Br-R-Br) as Bromine does not form hydrogen bonds. There are different types of Van der Waals Forces such as Dipole-Dipole force, ion- Dipole force, London force etc.
Between these two, Hydrogen bonds are stronger than the Van der Waals Forces as Van der Waals Forces are the weakest forces of all.
Van der Waals forces are important for establishing the bonds between the molecules as it is connected to the size of the molecules.
Van der Waals Force ∝ Surface Area ∝ Size ∝ Molecular mass
Some of the cases within Alkyl Halides to establish the relation with the boiling point are:
- Order of Boiling point in different Alkyl Halides:
CH3-F , CH3-Cl , CH3- Br , CH3-I
As the molecule having a bigger size has a greater Boiling point. And we studied above that the Boiling Point depends upon the Intermolecular forces (Van der Waals Force) and Van der Waals Force depends on the size of the molecule.
So, we know that the molecular size of Halides is in the order:
F < Cl < Br < I
So the order of Boiling point of Alkyl Halide can be given as-
CH3-F < CH3-Cl < CH3- Br < CH3-I
- Order of Boiling Point between a Alcohol and a Alkyl Halide:
CH3- OH and CH3-Cl
As the force of attraction between the molecules of alcohols is Hydrogen bond and between the molecules of Alkyl Halides it is Van der Waals forces. Since, the Hydrogen Bond is stronger than the Van der Waals forces therefore, the Boiling point of Alcohol is more than the Alkyl Halide.
CH3- OH > CH3-Cl
- Order of Boiling Point between Alkane and Alkyl Halide:
CH3-CH2-CH3 and CH3-CH2-CH2-Cl
Both of them have the Van der Waals forces and no hydrogen bonds. But in Alcohol molecules, there is a London force (a type of Van der Waals forces) as these are also Non-Polar molecules. On the other hand, in Alkyl Halide molecules experience a Dipole- Dipole force of attraction (another type of Van der Waals forces) as Chlorine is more electronegative than Carbon or they are Polar molecules.
Since, Dipole- Dipole force is stronger than London forces therefore the boiling point of Alkyl Halide is stronger than Alkane as it depends on the Van der Waals forces.
CH3-CH2-CH3 < CH3-CH2-CH2-Cl
(Alkane) (Alkyl Halide)
- Order of Boiling Points between isomeric Alkyl Halide:
In the case of Isomeric Alkyl Halide, as the branching increases the boiling point decreases. So, we can write as: Boiling Point ∝ Branching
This happens because as the branching increases, the molecule turns to take a spherical shape and we know that spherical shape tends to have the minimum surface area and therefore it leads to weak Van der Waals forces between the molecules or weak boiling points.
Therefore the order of Boiling Point will be:

Order of Boiling Point between isomeric Alkyl Halide
- Order of Boiling Point of Haloarenes:
Boiling points of haloarenes follow the order:
Iodoarene > Bromoarene > Chloroarene.
The order of boiling point of monohalogen derivatives of benzene is in the order as- iodo > bromo > chloro > fluoro. Moreover, the boiling point of isomeric di-haloarenes is almost similar.
3. Melting Point-
Melting Point of a structure depends on the lattice structure of the compound. And the molecules having efficient packaging have high melting points as it requires larger force of attraction to break the structure.
- Order of Melting Point between the different positions of Halobenzenes ( Aryl Halide):

Melting Point between the different positions of Halobenzenes:
In Halobenzenes, the Para isomers have a higher melting point than ortho and Meta isomers because in Para isomers there is symmetry in the crystal lattice of the structure.
4. Density-
We know that Density = MassVolume
Now the relation between the halogens in terms of their volume will be:
CH3-F < CH3- Cl < CH3-Br < CH3-I
Volume increases as the size of the molecule increases and due to this the mass of the molecule also increases. On moving down the group of halides both the volume and mass increases.
Therefore, if there is an increase in Mass as compared to volume then there will be an increase in Density as the Mass & Density are directly proportional to each other.
But if there is an increase in Volume as compared to Mass and we know that Volume & Density are indirectly proportional to each other, then there will be a decrease in the Density.
Here is the order of density of alkyl halides with the density-
| Compound | Density ( g/ml) |
|---|---|
| n-C3H7Cl | 0.89 |
| n-C3H7Br | 1.335 |
| n-C3H7I | 1.747 |
Density will be:
n-C3H7Cl < n-C3H7Br < n-C3H7I ( as the size increases)
Order of density of alkyl halides when number of halogen increases-
| Compound | Density ( g/ml) |
|---|---|
| CH2Cl2 | 1.336 |
| CHCl3 | 1.489 |
| CCl4 | 1.595 |
Density will be:
CH2Cl2 < CHCl3 < CHCl4 (as the number of halogen group increases)
5. Solubility-
In case of Alkyl Halide, it does not form hydrogen bonds with water molecules as the halogen group is not bonded with the hydrogen part of the alkyl group. Therefore it is not possible that the alkyl halide gets soluble in water. Although it will form a new bond whenever alkyl halide is mixed with water after breaking the earlier bonds between the molecules.

Solubility of alkyl halides
Hence the Alkyl Halides are not soluble or less soluble in water as it will not form the bond with water due to lack of sufficient energy. And they are soluble in Non-polar solvents (organic solvents like- ether, benzene, etc.).
In case of Haloarenes- They are the non-polar compound which cannot form the hydrogen bond with water molecules. As a result, Haloarenes are insoluble in water but they are soluble in organic solvents.
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Previous Year Questions
Ques. Explain why :
(a) The dipole moment of chlorobenzene is lower than that of cyclohexyl chloride.
(b) Alkyl halides, though polar, are immiscible with water. (Comptt. All India 2013, 2 Marks)
Ans. (a) Due to lower magnitude of -ve charge on the Cl atom and shorter C – Cl distance, chlorobenzene has a lower dipole moment than the cyclohexyl chloride. A sp2-hybrid carbon is more electronegative than a sp3-hybrid carbon. Due to this the sp2-hybrid carbon of C – Cl bond in chlorobenzene has less tendency to release electrons to Cl than a sp3 hybrid carbon of cyclohexyl chloride.

(b) Alkyl halides and polar molecules are held together by dipole-dipole interaction. The molecules of H2O are held together by H- bonds. Since the forces of attraction between water and alkyl halide molecules are weaker than the forces of attraction between alkyl halide-alkyl halide molecules and water-water molecules that is why alkyl halides are immiscible (not soluble) with water.
Ques. Answer the following :
(i) Haloalkanes easily dissolve in organic solvents, why?
(ii) What is known as a racemic mixture? Give an example.
(iii) Of the two bromo derivatives, C6H5CH (CH3)Br and C6H5CH(C6H5)Br, which one is more reactive in SN1 substitution reaction and why? (Delhi 2011, 3 Marks)
Ans. (i) Haloalkanes get easily dissolved in the organic solvent because the new forces of attraction between haloalkanes and solvent molecules and the forces of attraction being broken are of the same strength.
(ii) A mixture having the equal proportions of two enantiomers of a compound is called racemic mixture. Example : (±) butan-2-ol
(iii) The reactivity of SN1 reactions increases as the stability of intermediate carbocation increases. In 2° bromides, the carbocation is derived from C6H5CH(C6H5)Br i.e. C6H5CHC6H5 is more stable as compared to the carbocation C6H+5CH(CH3) obtained from C6H5CH(CH3)Br because it is stabilized by two phenyl groups due to resonance.
Ques. Give reasons :
(a) n-Butyl bromide has higher boiling point than f-butyl bromide.
(b) Racemic mixture is optically inactive.
(c) The presence of nitro group (-NO2) at o/p positions increases the reactivity of haloarenes towards nucleophilic substitution reactions. (Delhi 2015, 3 Marks)
Ans. (a) n-Butyl bromide has higher boiling point than f-butyl bromide because n-Butyl bromide has larger surface area due to which it has more Van der Waals’ forces.
(b) Rotation due to one enantiomer is cancelled by another enantiomer that is why Racemic Mixture is optically inactive.
(c) The presence of nitro group (-NO2)at ortho and para positions withdraws the electron density from the benzene ring due to which it increases the attack of nucleophile.
Ques. What happens when
(i) CH3—Cl is treated with aqueous KOH?
(ii) CH3—Cl is treated with KCN?
(iii) CH3—Br is treated with Mg in the presence of dry ether? (Comptt. All India 2016, 3 Marks)
Ans.

Methyl magnesium bromide
Ques. (a) Why are alkyl halides insoluble in water?
(b) Why is Butan-1-ol optically inactive but Butan-2-ol is optically active?
(c) Although chlorine is an electron withdrawing group, yet it is ortho-, Para- directing in electrophilic aromatic substitution reaction. Why? (CBSE 2015, 3 Marks)
Ans. (a) Alkyl halides are insoluble in water because they can neither form H-bonds with water nor they can break H-bonds between water molecules.
(b) Butan-1-ol is optically inactive because Butan-1-ol is achiral, i.e. does not have chiral ‘C’ atom which is attached to four different groups.

(c) Although -Cl is electron withdrawing (-I effect) but still ortho and para directing as due to +R effect.

Ques. Explain as to why
(i) Alkyl halides, though polar, are immiscible with water.
(ii) Grignard’s reagent should be prepared under anhydrous conditions. (All India 2014, 2 Marks)
Ans. (i) Alkyl halides cannot form H-bonds with water due to which they are immiscible (insoluble) with water.
(ii) Grignard reagent should be prepared in absence of water, i.e. anhydrous conditions because the Grignard reagent reacts with water to form alkane.
Sample Questions
Ques. Arrange the set of compounds in order of increasing boiling points.
Bromomethane, Bromoform, Chloromethane, Dibromomethane.(2 marks)
Ans. The structure of the compound will be: CH3-Br, CHBr3, CH3-Cl, CH2- Br2
Chlorine has less mass than Bromine; therefore it will come first and has the lowest Boiling point. All the rest structures have Bromine but in increasing number and we as the number of halogen group increases there is increase in Boiling point. So, the final relation will be:
CH3-Cl < CH3-Br < CH2- Br2 3
Ques. Arrange the set of compounds in order of increasing boiling points: 1-Chloropropane, Isopropyl chloride, 1-Chlorobutane.(1 mark)
Ans. As the branching increases the Boiling point of the compound decreases:
Isopropyl Chloride< 1- Chlorobutane< 1- Chloropropane
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