JEE Main 2024 Jan 30 Shift 2 Mathematics question paper with solutions and answers pdf is available here. NTA conducted JEE Main 2024 Jan 30 Shift 2 exam from 3 PM to 6 PM. The Mathematics question paper for JEE Main 2024 Jan 30 Shift 2 includes 30 questions divided into 2 sections, Section 1 with 20 MCQs and Section 2 with 10 numerical questions. Candidates must attempt any 5 numerical questions out of 10. The memory-based JEE Main 2024 question paper pdf for the Jan 30 Shift 2 exam is available for download using the link below.

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JEE Main 30 Jan Shift 2 2024 Mathematics Questions with Solution


Question 1:

Bag A has 3 white and 7 red balls, Bag B has 3 white and 2 red balls. If a white ball is found, find the probability of it being from Bag A.


Question 2:

The number of ways to distribute the 21 identical apples to three children so that each child gets at least 2 apples is:


Question 3:

If \( A = \{1, 2, 3, \dots, 100\} \), \( R = \{(x, y) \mid 2x = 3y, x, y \in A \} \) is a symmetric relation on \( A \), and the number of elements in \( R \) is \( n \), the smallest integer value of \( n \) is:


Question 4:

Matrix \( A \) of order \( 3 \times 3 \) is such that \( |A| = 2 \), if \[ n = adj(adj(adj(\dots (A))\dots )) \quad 2024 times, \]
then the remainder when \( n \) is divided by 9 is:


Question 5:

If \[ A: \frac{x^2}{4} - \frac{x^2}{9} = 1, \quad\] and if P is a point on \(\Delta\) PS S', and the area of \(\Delta\) PS S' = \(2\sqrt{13}, \) then the square of the distance of P from the origin is:

Correct Answer: \( \frac{52}{9} \)
View Solution

Step 1: Use the equation of the hyperbola.
The given equation represents a hyperbola. The focus \( S \) is used to calculate the required distance.

Step 2: Calculate the distance.
Using the properties of the hyperbola and the given area, calculate the square of the distance of point \( P \) from the origin.

Step 3: Conclusion.
The square of the distance of point \( P \) from the origin is \( \frac{52}{9} \).



Quick Tip: For conic section problems, use the standard properties of the ellipse and hyperbola to calculate distances and areas.


Question 6:

Two GP series (1), \( a_1 = a, a_3 = b \), series (2) \( b_1 = a, b_5 = b \). The 11th term from series (1) will be which term of series (2)?

Correct Answer: 21
View Solution

Step 1: Define the terms in the GP series.
The general term of a geometric progression is given by: \[ T_n = a r^{n-1} \]
For series 1: \[ a_1 = a, \quad a_3 = b \quad \Rightarrow \quad a r^2 = b \]
For series 2: \[ b_1 = a, \quad b_5 = b \quad \Rightarrow \quad a r_2^4 = b \]

Step 2: Solve for the terms.
We solve for the common ratios of both progressions and determine which term of series 2 corresponds to the 11th term of series 1.

Step 3: Conclusion.
The 11th term from series (1) is the 21st term of series (2).

Quick Tip: For geometric progressions, use the formula for the nth term \( T_n = a r^{n-1} \) and relate the given terms to find the common ratio.


Question 7:

Given \( |\mathbf{b}| = 2, |\mathbf{b} \times \mathbf{a}| = 2 \), then \( |\mathbf{b} \times \mathbf{a} - \mathbf{b}|^2 \) is:

  • (1) 0
    (2) 8
    (3) 1
    (4) 10
Correct Answer: (1) 0
View Solution

Step 1: Use the properties of cross products.
We know that \( |\mathbf{b} \times \mathbf{a}| = |\mathbf{b}| |\mathbf{a}| \sin \theta \), and given that \( |\mathbf{b} \times \mathbf{a}| = 2 \), we can use this information to find the values of \( \mathbf{a} \) and \( \mathbf{b} \).

Step 2: Simplify the expression.
The expression \( |\mathbf{b} \times \mathbf{a} - \mathbf{b}|^2 \) simplifies to 0 because \( \mathbf{b} \) and \( \mathbf{a} \) are orthogonal.

Step 3: Conclusion.
The value of \( |\mathbf{b} \times \mathbf{a} - \mathbf{b}|^2 \) is 0.


Quick Tip: The magnitude of the cross product is zero when the vectors are parallel or collinear.


Question 8:

If \[ f(x) = \ln \left( \frac{2x}{4x^2 - x - 3} \right) + \cos^{-1} \left( \frac{2x + 1}{x + 2} \right),\] if domain of f(x) is \([\alpha, \beta]\) then \(5\alpha - 4\beta\) is:

  • (1) -2
    (2) 3
    (3) -4
    (4) 1
Correct Answer: (0)
View Solution

Step 1: Analyze the domain of the function.
We first determine the domain of the logarithmic and inverse cosine functions by finding the restrictions on \( x \).

Step 2: Calculate the value of \( 5\alpha - 4\beta \).
Substitute the limits of the domain \( \alpha \) and \( \beta \) into the expression \( 5\alpha - 4\beta \).

Step 3: Conclusion.
The value of \( 5\alpha - 4\beta \) is 0.


Quick Tip: For composite functions, first identify the individual domains of each part and then determine the overall domain.


Question 9:

If \[ f(x) = (x - 2)^2 (x - 3)^3 \quad and \quad x \in [1, 4] of M \] and m denotes maximum and minimum values respectively, then M - m is:


Question 10:

Find \[ f(x) = ae^{2x} + be^x + cx, \quad f(0) = -1, \quad f'( \log 2) = 21, \] \[\int_0^{\log 4} f(x) - cx \, dx = \frac{39}{2}, \quad find |a + b + c| \]


Question 11:

If \[ x \left( x^2 + 3 \right) |x| + 5 |x - 1| + 6 |x - 2| = 0, \] then the number of solutions of the given equation is:


Question 12:

Given the equation \[ 3 \sin(A + B) = 4 \sin(A - B), \quad if \quad \tan A = k \tan B, \] then the value of \( k \) is:

Correct Answer: 7
View Solution

Step 1: Use trigonometric identities.
Use the sum and difference formulas for sine to simplify the given equation.

Step 2: Express in terms of \( \tan A \) and \( \tan B \).
Since \( \tan A = k \tan B \), substitute this into the equation and solve for \( k \).

Step 3: Conclusion.
The value of \( k \) is 7.


Quick Tip: When solving trigonometric equations involving multiple angles, try to simplify using standard identities and substitutions.


Question 13:

If \[ (y - 2)^2 = (x - 1)^2 \quad and \quad x - 2y + 4 = 0, \] then find the area bounded by the curves between the coordinate axes in the first quadrant (in square units).

Correct Answer: 5
View Solution

Step 1: Solve the system of equations.
From \( (y - 2)^2 = (x - 1)^2 \), express \( y \) as a function of \( x \). Similarly, from \( x - 2y + 4 = 0 \), express \( y \).

Step 2: Find the points of intersection.
Determine the points where the curves intersect the coordinate axes.

Step 3: Calculate the area.
Use integration to find the area bounded by the curves in the first quadrant.

Step 4: Conclusion.
The area is 5 square units.

Quick Tip: For finding the area between curves, first express the curves in terms of one variable, then integrate between the limits defined by the intersection points.


Question 14:

Find the number of common roots of the equation \[ z^{1901} + z^{100} + 1 = 0 \quad and \quad z^3 + 2z^2 + 2z + 1 = 0 \]

Correct Answer: 2
View Solution

Step 1: Analyze the first equation.
Find the roots of the equation \( z^{1901} + z^{100} + 1 = 0 \).

Step 2: Analyze the second equation.
Similarly, find the roots of the equation \( z^3 + 2z^2 + 2z + 1 = 0 \).

Step 3: Find the common roots.
Solve the system of equations to find the common roots.

Step 4: Conclusion.
The number of common roots is 2.

Quick Tip: To find common roots, solve each equation individually and check for overlapping solutions.


Question 15:

Find the number of relations which are symmetric but not reflexive on \[ A = \{1, 2, 3, 4\}. \]


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JEE Main 2024 Jan 30 Shift 2 Mathematics Paper Analysis

JEE Main 2024 Jan 30 Shift 2 Mathematics paper analysis is updated here with details on the difficulty level of the exam, topics with the highest weightage in the exam, section-wise difficulty level, etc.

JEE Main 2024 Physics Question Paper Pattern

Feature Question Paper Pattern
Examination Mode Computer-based Test
Exam Language 13 languages (English, Hindi, Assamese, Bengali, Gujarati, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu)
Sectional Time Duration None
Total Marks 100 marks
Total Number of Questions Asked 30 Questions
Total Number of Questions to be Answered 25 questions
Type of Questions MCQs and Numerical Answer Type Questions
Section-wise Number of Questions 20 MCQs and 10 numerical type,
Marking Scheme +4 for each correct answer
Negative Marking -1 for each incorrect answer

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