NEET PYQs for Moment of Inertia with Solutions: Practice NEET Previous Year Questions

Updated on - Jan 19, 2026

Moment of Inertia is an important topic in the Physics section in NEET exam. Practising this topic will increase your score overall and make your conceptual grip on NEET exam stronger.

This article gives you a full set of NEET PYQs for Moment of Inertia with explanations for effective preparation. Practice of NEET Physics PYQs including Moment of Inertia questions regularly will improve accuracy, speed, and confidence in the NEET 2026 exam.

NEET PYQs for Moment of Inertia with Solutions

1.
The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm². The length of the 400 g rod is nearly :
- 8.5 cm
- 17.5 cm
- 20.7 cm
- 72.0 cm
View Solution
2.
Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities ω₁ and ω₂. They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is
- $\frac 12l(ω_1+ω_2)^2$
- $\frac 14l(ω_1-ω_2)^2$
- $l(ω_1-ω_2)^2$
- $\frac 18(ω_1-ω_2)^2$
View Solution
3.
The ratio of the accelerations for a solid sphere (mass m and radius R) rolling down an incline of angle $ \theta $ without slipping and slipping down the incline without rolling is
- 5 : 7
- 2 : 3
- 2 : 5
- 7 : 5
View Solution
4.
The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius, about an axis passing through their centres and perpendicular to their planes are :
- $ 1: \sqrt 2 $
- 3 : 2
- 2 : 1
- $ \sqrt 2 :1 $
View Solution
5.
Two identical concentric rings each of mass $m$ and radius $R$ are placed perpendicularly. What is the moment of inertia about axis of one of the rings
- $\frac{3}{2}MR^2$
- $2MR^2$
- $3MR^2$
- $\frac{1}{4}MR^2$
View Solution
6.
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :
- $ \frac{7}{40} $
- $ \frac{7}{57} $
- $ \frac{7}{64} $
- $ \frac{7}{8} $
View Solution
7.
$A$ uniform rod of length $200\, cm$ and mass $500\, g$ is balanced on a wedge placed at $40\, cm$ mark. A mass of $2\, kg$ is suspended from the rod at $20\, cm$ and another unknown mass ' $m$ ' is suspended from the rod at $160\, cm$ mark as shown in the figure Find the value of 'm' such that the rod is in equilibrium. $\left( g =10\, m / s ^{2}\right)$
- $\frac{1}{2} kg$
- $\frac{1}{3} kg$
- $\frac{1}{6} kg$
- $\frac{1}{12} kg$
View Solution
8.
The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis touching the disc at its diameter and normal to the disc is :
- $\frac{1}{2}MR^2$
- $MR^2$
- $\frac{2}{5}MR^2$
- $\frac{3}{2}MR^2$
View Solution
9.
Moment of inertia of ring about its diameter is $ I. $ Then, moment of inertia about an axis passing through centre perpendicular to its plane is
- $ 2I $
- $ \frac{I}{2} $
- $ \frac{3}{2}I $
- $ I $
View Solution
10.
The radius of gyration of a solid sphere of mass $5 \, \text{kg}$ about $XY$ is $5 \, \text{m}$ as shown in figure.
The radius of the sphere is $\frac{5x}{\sqrt{7}} \, \text{m}$, then the value of $x$ is:
- $5$
- $\sqrt{2}$
- $\sqrt{3}$
- $\sqrt{5}$
View Solution

View more NEET Questions

SHARE ON FACEBOOK SHARE ON TWITTER

Comments

No Comments To Show

SUBSCRIBE TO OUR NEWS LETTER

COLLEGE NOTIFICATIONS

EXAM NOTIFICATIONS

NEWS UPDATES

Download the Collegedunia app on

NEET PYQs for Moment of Inertia with Solutions

1.The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm2. The length of the 400 g rod is nearly :

3.The ratio of the accelerations for a solid sphere (mass m and radius R) rolling down an incline of angle $ \theta $ without slipping and slipping down the incline without rolling is

4.The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius, about an axis passing through their centres and perpendicular to their planes are :

5.Two identical concentric rings each of mass $m$ and radius $R$ are placed perpendicularly. What is the moment of inertia about axis of one of the rings

6.A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :

8.The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis touching the disc at its diameter and normal to the disc is :

9.Moment of inertia of ring about its diameter is $ I. $ Then, moment of inertia about an axis passing through centre perpendicular to its plane is

10.The radius of gyration of a solid sphere of mass \(5 \, \text{kg}\) about \(XY\) is \(5 \, \text{m}\) as shown in figure.The radius of the sphere is \(\frac{5x}{\sqrt{7}} \, \text{m}\), then the value of \(x\) is:

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm². The length of the 400 g rod is nearly :

3.
The ratio of the accelerations for a solid sphere (mass m and radius R) rolling down an incline of angle $ \theta $ without slipping and slipping down the incline without rolling is

4.
The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius, about an axis passing through their centres and perpendicular to their planes are :

5.
Two identical concentric rings each of mass $m$ and radius $R$ are placed perpendicularly. What is the moment of inertia about axis of one of the rings

6.
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :

8.
The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis touching the disc at its diameter and normal to the disc is :

9.
Moment of inertia of ring about its diameter is $ I. $ Then, moment of inertia about an axis passing through centre perpendicular to its plane is

10.
The radius of gyration of a solid sphere of mass \(5 \, \text{kg}\) about \(XY\) is \(5 \, \text{m}\) as shown in figure.
The radius of the sphere is \(\frac{5x}{\sqrt{7}} \, \text{m}\), then the value of \(x\) is: