NEET PYQs for Motion In a Plane with Solutions: Practice NEET Previous Year Questions

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Motion In a Plane is an important topic in the Physics section in NEET exam. Practising this topic will increase your score overall and make your conceptual grip on NEET exam stronger.

This article gives you a full set of NEET PYQs for Motion In a Plane with explanations for effective preparation. Practice of NEET Physics PYQs including Motion In a Plane questions regularly will improve accuracy, speed, and confidence in the NEET 2026 exam.

NEET PYQs for Motion In a Plane with Solutions

1.
A particle moves in a circle of radius $5 \,cm$ with constant speed and time period $0.2 \,\pi\, s$. The acceleration of the particle is
- $15 \,m/s^2 $
- $25 \,m/s^2 $
- $36 \,m/s^2 $
- $5 \, m/s^2 $
View Solution
2.
A projectile is fired at an angle of $45^\circ$ with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is
- $ 45^\circ$
- $60^\circ$
- $ \tan^{ - 1} \frac{1}{2}$
- $ \tan^{ - 1} \bigg( \frac{\sqrt 3}{2}\bigg)$
View Solution
3.
If vectors $ \overrightarrow{A} = \cos \, \omega t \, \widehat{ i} + \sin \, \omega \, t \widehat{j}$ and $ \overrightarrow{ B} = \cos \, \frac{ \omega \, t }{ 2} \widehat{i} + \sin \, \frac{ \omega \, t }{ 2} \widehat{j}$ are functions of time, then the value of $t$ at which they are orthogonal to each other is
- t = $ \frac{ \pi}{ \omega } $
- t = 0
- t = $ \frac{ \pi}{ 4 \omega } $
- t = $ \frac{ \pi}{2 \omega } $
View Solution
4.
The angular acceleration of a body, moving along the circumference of a circle, is:
- along the axis of rotation
- along the radius, away from center
- along the radius towards the centre
- along the tangent to its position
View Solution
5.
A bullet is fired from a gun at the speed of 280 ms^-1 in the direction 30° above the horizontal. The maximum height attained by the bullet is
(g = 9.8 ms^-2, sin 30° = 0.5)
- 3000 m
- 2800 m
- 2000 m
- 1000 m
View Solution
6.
A body is moving with velocity $30\, ms$ towards east After 10 s its velocity becomes $40 \,ms$ towards north. The average acceleration of the body is
- $7\, ms^{-1}$
- $\sqrt{7}\,ms^{-1}$
- $5\,ms^{-1}$
- $1 \,ms^{-2}$
View Solution
7.
A ship A is moving Westwards with a speed of 10 km $h^{ - 1}$ and a ship B 100 km South of A, is moving Northwards with a speed of 10 km $ h^{ - 1}$. The time after which the distance between them becomes shortest, is
- 5 $ \sqrt 2 $ h
- 10 $ \sqrt 2 $ h
- 0 h
- 5 h
View Solution
8.
A projectile is fired from the surface of the earth with a velocity of $5\, m s^{- 1}$ and angle $\theta$ with the horizontal. Another projectile fired from another planet with a velocity of $3\,ms^{ - 1}$ at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in $ms^{ - 2}$ ) is (Given $g= 9.8 \,ms^{ - 2}$)
- 3.5
- 5.9
- 16.3
- 110.8
View Solution
9.
A missile is fired for maximum range with an initial velocity of $20\, m/s$. If $g = 10 \,m/s^2$, the range of the missile is
- 40 m
- 50 m
- 60 m
- 20 m
View Solution
10.
A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V0 m/s in the $n^{th}$ round. Its angular acceleration will be :-
- $\frac{\vee_{0}}{n}rad / s^{2}$
- $\frac{\vee^{2}_{0}}{2\pi nr^{2}}rad / s^{2}$
- $\frac{\vee^{2}_{0}}{4\pi nr^{2}}rad / s^{2}$
- $\frac{\vee^{4}_{0}}{4\pi nr}rad / s^{2}$
View Solution
11.
In the given figure, $a =15\, m / s ^{2}$ represents the total acceleration of a particle moving in the clockwise direction in a circle of radius $R =2.5\, m$ at a given instant of time. The speed of the particle is -
- 4.5 m/s
- 5.0 m/s
- 5.7 m/s
- 6.2 m/s
View Solution
12.
A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t = 0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at time t = 5 s. Average velocity vector $ ( \vec{ v_{av}})$ from t = 0 to t = 5 s is .
- $ \frac{ 1}{ 5} (13 \widehat{ i} + 14 \widehat{j}) $
- $ \frac{ 7}{ 3} ( \widehat{i} + \widehat{j})$
- 2 $ ( \widehat{i} + \widehat{j})$
- $ \frac{11}{ 5} ( \widehat{i} + \widehat{j})$
View Solution
13.
A particle has initial velocity $ ( 2 \vec{i} + 3 \vec{j})$ and acceleartion ($ 0 . 3 \vec{i} + 0 . 2 \vec{j})$ The magnitude of velocity after 10 seconds will be
- 9 $ \sqrt 2 $ units
- 5 $ \sqrt 2 $ units
- 5 units
- 9 units
View Solution
14.
In the product $\vec{F}=q(\vec{v}\times\vec{b})$
=$q\vec{v}\times(B\hat i+B \hat j+B_0\hat k)$
For q=1 and $\vec v = 2\hat i+4\hat j+6\hat k$ and $\vec F=4\hat i-20\hat j+12\hat k$
What will be the complete expression for $\vec B$ ?
- $6\hat i+6\hat j-8\hat k$
- $-8\hat i-8\hat j-6\hat k$
- $-6\hat i-6\hat j-8\hat k$
- $8\hat i+8\hat j-6\hat k$
View Solution
15.
When an object is shot from the bottom of a long smooth inclined plane kept at an angle $60^\circ$ with horizontal, it can travel a distance $x_1$ along the plane. But when the inclination is decreased to $30^{\circ}$ and the same object is shot with the same velocity, it can travel $x_2$ distance. Then $x_1$ : $x_2$ will be:
- $1:\sqrt{3}$
- $1: 2\sqrt{3}$
- $1:\sqrt{2}$
- $\sqrt{2}:1$
View Solution

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NEET PYQs for Motion In a Plane with Solutions: Practice NEET Previous Year Questions

NEET PYQs for Motion In a Plane with Solutions

1.
A particle moves in a circle of radius $5 \,cm$ with constant speed and time period $0.2 \,\pi\, s$. The acceleration of the particle is

2.
A projectile is fired at an angle of $45^\circ$ with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is

4.
The angular acceleration of a body, moving along the circumference of a circle, is:

5.
A bullet is fired from a gun at the speed of 280 ms^-1 in the direction 30° above the horizontal. The maximum height attained by the bullet is
(g = 9.8 ms^-2, sin 30° = 0.5)

6.
A body is moving with velocity $30\, ms$ towards east After 10 s its velocity becomes $40 \,ms$ towards north. The average acceleration of the body is

7.
A ship A is moving Westwards with a speed of 10 km $h^{ - 1}$ and a ship B 100 km South of A, is moving Northwards with a speed of 10 km $ h^{ - 1}$. The time after which the distance between them becomes shortest, is

9.
A missile is fired for maximum range with an initial velocity of $20\, m/s$. If $g = 10 \,m/s^2$, the range of the missile is

10.
A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V0 m/s in the $n^{th}$ round. Its angular acceleration will be :-

11.
In the given figure, $a =15\, m / s ^{2}$ represents the total acceleration of a particle moving in the clockwise direction in a circle of radius $R =2.5\, m$ at a given instant of time. The speed of the particle is -

12.
A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t = 0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at time t = 5 s. Average velocity vector $ ( \vec{ v_{av}})$ from t = 0 to t = 5 s is .

13.
A particle has initial velocity $ ( 2 \vec{i} + 3 \vec{j})$ and acceleartion ($ 0 . 3 \vec{i} + 0 . 2 \vec{j})$ The magnitude of velocity after 10 seconds will be

14.
In the product \(\vec{F}=q(\vec{v}\times\vec{b})\)
=\(q\vec{v}\times(B\hat i+B \hat j+B_0\hat k)\)
For q=1 and \(\vec v = 2\hat i+4\hat j+6\hat k\) and \(\vec F=4\hat i-20\hat j+12\hat k\)
What will be the complete expression for \(\vec B\) ?

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NEET PYQs for Motion In a Plane with Solutions

1.A particle moves in a circle of radius $5 \,cm$ with constant speed and time period $0.2 \,\pi\, s$. The acceleration of the particle is

2.A projectile is fired at an angle of $45^\circ$ with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is

4.The angular acceleration of a body, moving along the circumference of a circle, is:

5.A bullet is fired from a gun at the speed of 280 ms-1 in the direction 30° above the horizontal. The maximum height attained by the bullet is(g = 9.8 ms-2, sin 30° = 0.5)

6.A body is moving with velocity $30\, ms$ towards east After 10 s its velocity becomes $40 \,ms$ towards north. The average acceleration of the body is

7.A ship A is moving Westwards with a speed of 10 km $h^{ - 1}$ and a ship B 100 km South of A, is moving Northwards with a speed of 10 km $ h^{ - 1}$. The time after which the distance between them becomes shortest, is

9.A missile is fired for maximum range with an initial velocity of $20\, m/s$. If $g = 10 \,m/s^2$, the range of the missile is

10.A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V0 m/s in the $n^{th}$ round. Its angular acceleration will be :-

11.In the given figure, $a =15\, m / s ^{2}$ represents the total acceleration of a particle moving in the clockwise direction in a circle of radius $R =2.5\, m$ at a given instant of time. The speed of the particle is -

12.A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t = 0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at time t = 5 s. Average velocity vector $ ( \vec{ v_{av}})$ from t = 0 to t = 5 s is .

13.A particle has initial velocity $ ( 2 \vec{i} + 3 \vec{j})$ and acceleartion ($ 0 . 3 \vec{i} + 0 . 2 \vec{j})$ The magnitude of velocity after 10 seconds will be

14.In the product \(\vec{F}=q(\vec{v}\times\vec{b})\) =\(q\vec{v}\times(B\hat i+B \hat j+B_0\hat k)\) For q=1 and \(\vec v = 2\hat i+4\hat j+6\hat k\) and \(\vec F=4\hat i-20\hat j+12\hat k\)What will be the complete expression for \(\vec B\) ?

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1.
A particle moves in a circle of radius $5 \,cm$ with constant speed and time period $0.2 \,\pi\, s$. The acceleration of the particle is

2.
A projectile is fired at an angle of $45^\circ$ with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is

4.
The angular acceleration of a body, moving along the circumference of a circle, is:

5.
A bullet is fired from a gun at the speed of 280 ms^-1 in the direction 30° above the horizontal. The maximum height attained by the bullet is
(g = 9.8 ms^-2, sin 30° = 0.5)

6.
A body is moving with velocity $30\, ms$ towards east After 10 s its velocity becomes $40 \,ms$ towards north. The average acceleration of the body is

7.
A ship A is moving Westwards with a speed of 10 km $h^{ - 1}$ and a ship B 100 km South of A, is moving Northwards with a speed of 10 km $ h^{ - 1}$. The time after which the distance between them becomes shortest, is

9.
A missile is fired for maximum range with an initial velocity of $20\, m/s$. If $g = 10 \,m/s^2$, the range of the missile is

10.
A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V0 m/s in the $n^{th}$ round. Its angular acceleration will be :-

11.
In the given figure, $a =15\, m / s ^{2}$ represents the total acceleration of a particle moving in the clockwise direction in a circle of radius $R =2.5\, m$ at a given instant of time. The speed of the particle is -

12.
A particle is moving such that its position coordinates (x, y) are (2 m, 3 m) at time t = 0, (6 m, 7 m) at time t = 2 s and (13 m, 14 m) at time t = 5 s. Average velocity vector $ ( \vec{ v_{av}})$ from t = 0 to t = 5 s is .

13.
A particle has initial velocity $ ( 2 \vec{i} + 3 \vec{j})$ and acceleartion ($ 0 . 3 \vec{i} + 0 . 2 \vec{j})$ The magnitude of velocity after 10 seconds will be

14.
In the product \(\vec{F}=q(\vec{v}\times\vec{b})\)
=\(q\vec{v}\times(B\hat i+B \hat j+B_0\hat k)\)
For q=1 and \(\vec v = 2\hat i+4\hat j+6\hat k\) and \(\vec F=4\hat i-20\hat j+12\hat k\)
What will be the complete expression for \(\vec B\) ?