NEET PYQs for Waves and Oscillations with Solutions: Practice NEET Previous Year Questions

Updated 3+ months ago

Waves and Oscillations is an important topic in the Physics section in NEET exam. Practising this topic will increase your score overall and make your conceptual grip on NEET exam stronger.

This article gives you a full set of NEET PYQs for Waves and Oscillations with explanations for effective preparation. Practice of NEET Physics PYQs including Waves and Oscillations questions regularly will improve accuracy, speed, and confidence in the NEET 2026 exam.

NEET PYQs for Waves and Oscillations with Solutions

1.
In an oscillating spring mass system, a spring is connected to a box filled with sand. As the box oscillates, sand leaks slowly out of the box vertically so that the average frequency Ï‰(t) and average amplitude A(t) of the system change with time t. Which one of the following options schematically depicts these changes correctly?
- Figure 1
- Figure 2
- Figure 3
- Figure 4
View Solution
2.
A particle is executing SHM along a straight line. It velocities at distances $x_1$ and $x_2$ mean position are $V_1$ and $V_2$, respecilvely. Its time period is :
- $2 \pi \sqrt{\frac{V_1^2 + V_2^2}{x_1^2 + x_2^2}}$
- $2 \pi \sqrt{\frac{V_1^2 - V_2^2}{x_1^2 - x_2^2}}$
- $2 \pi \sqrt{\frac{x_1^2 + x_2^2}{V_1^2 + V_2^2}}$
- $2 \pi \sqrt{\frac{x_2^2 - x_1^2}{V_1^2 - V_2^2}}$
View Solution
3.
Two identical point masses P and Q, suspended from two separate massless springs of spring constants $k_1$ and $k_2$, respectively, oscillate vertically. If their maximum velocities are the same, the ratio of the amplitude of P to the amplitude of Q is :
- $ \sqrt{\frac{k_2}{k_1}} $
- $ \sqrt{\frac{k_1}{k_2}} $
- $ \frac{k_2}{k_1} $
- $ \frac{k_1}{k_2} $
View Solution
4.
A spring is stretched by 5 cm by a force of 10 N. The time period of the oscillations, when a mass of 2 kg is suspended by it, is
- 0.628 s
- 0.0628 s
- 6.28 s
- 3.14 s
View Solution
5.
Average velocity of a particle executing SHM in one complete vibration is :
- $\frac{A\,\omega^2}{2}$
- zero
- $\frac{A_\omega}{2}$
- $A_\omega$
View Solution
6.
A particle executes linear simple harmonic motion with an amplitude of $3 \,cm$. When the particle is at $2\,cm$ from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is :
- $\frac{\sqrt{5}}{2 \pi }$
- $\frac{4 \pi }{\sqrt{5}}$
- $\frac{2 \pi }{\sqrt{3}}$
- $\frac{\sqrt{5}}{ \pi }$
View Solution
7.
Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:
- 11
- 9
- 10
- 8
View Solution
8.
A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \, m/s^{-2}$ at a distance of $5 \,m$ from the mean position. The time period of oscillation is
- 1 s
- 2 $\pi$ s
- 2s
- $\pi s $
View Solution
9.
A body of mass $m$ is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass when the mass $m$ is slightly pulled down and released, it oscillates with a time period of $3\,s$. When the mass $m$ is increased by $1\,kg$, the time period of oscillations becomes $5\, s$. The value of $m$ in $kg$ is
- $\frac{3}{4}$
- $\frac{4}{3}$
- $\frac{16}{9}$
- $\frac{9}{16}$
View Solution
10.
The distance covered by a particle undergoing SHM in one time period is (amplitude = A) :
- zero
- A
- 2A
- 4A
View Solution
11.
The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:
- $\pi$ rad
- $\frac {3\pi}{2}$ rad
- $\frac {\pi}{2}$ rad
- $zero$
View Solution
12.
A spring of force constant $k$ is cut into lengths of ratio $1 : 2 : 3$. They are connected in series and the new force constant is $k'$. Then they are connected in parallel and force constant is $k"$ . Then $k' : k''$ is :
- 1 : 9
- 1 : 11
- 1 : 14
- 1 : 16
View Solution
13.
A particle is executing a simple harmonic motion. Its maximum acceleration is $\alpha$ and maximum velocity is $\beta$ Then, its time period of vibration will be
- $ \frac{ \beta^2}{ \alpha}$
- $ \frac{ 2 \pi \beta}{ \alpha} $
- $ \frac{ \beta^2}{ \alpha^2}$
- $ \frac{ \alpha}{ \beta} $
View Solution
14.
A body is executing simple harmonic motion with frequency ‘n’, the frequency of its potential energy is
- 4n
- n
- 2n
- 3n
View Solution
15.
A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k''. Then k' : k'' is
- 1 : 6
- 1 : 9
- 1 : 11
- 1 : 14
View Solution

View more NEET Questions

SHARE ON FACEBOOK SHARE ON TWITTER

Comments

No Comments To Show

SUBSCRIBE TO OUR NEWS LETTER

COLLEGE NOTIFICATIONS

EXAM NOTIFICATIONS

NEWS UPDATES

Download the Collegedunia app on

NEET PYQs for Waves and Oscillations with Solutions

2.A particle is executing SHM along a straight line. It velocities at distances $x_1$ and $x_2$ mean position are $V_1$ and $V_2$, respecilvely. Its time period is :

3.Two identical point masses P and Q, suspended from two separate massless springs of spring constants \(k_1\) and \(k_2\), respectively, oscillate vertically. If their maximum velocities are the same, the ratio of the amplitude of P to the amplitude of Q is :

4.A spring is stretched by 5 cm by a force of 10 N. The time period of the oscillations, when a mass of 2 kg is suspended by it, is

5.Average velocity of a particle executing SHM in one complete vibration is :

6.A particle executes linear simple harmonic motion with an amplitude of $3 \,cm$. When the particle is at $2\,cm$ from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is :

7.Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

8.A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \, m/s^{-2}$ at a distance of $5 \,m$ from the mean position. The time period of oscillation is

10.The distance covered by a particle undergoing SHM in one time period is (amplitude = A) :

11.The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:

12.A spring of force constant $k$ is cut into lengths of ratio $1 : 2 : 3$. They are connected in series and the new force constant is $k'$. Then they are connected in parallel and force constant is $k"$ . Then $k' : k''$ is :

13.A particle is executing a simple harmonic motion. Its maximum acceleration is $\alpha$ and maximum velocity is $\beta$ Then, its time period of vibration will be

14.A body is executing simple harmonic motion with frequency ‘n’, the frequency of its potential energy is

15.A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k''. Then k' : k'' is

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
A particle is executing SHM along a straight line. It velocities at distances $x_1$ and $x_2$ mean position are $V_1$ and $V_2$, respecilvely. Its time period is :

3.
Two identical point masses P and Q, suspended from two separate massless springs of spring constants \(k_1\) and \(k_2\), respectively, oscillate vertically. If their maximum velocities are the same, the ratio of the amplitude of P to the amplitude of Q is :

4.
A spring is stretched by 5 cm by a force of 10 N. The time period of the oscillations, when a mass of 2 kg is suspended by it, is

5.
Average velocity of a particle executing SHM in one complete vibration is :

6.
A particle executes linear simple harmonic motion with an amplitude of $3 \,cm$. When the particle is at $2\,cm$ from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is :

7.
Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

8.
A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \, m/s^{-2}$ at a distance of $5 \,m$ from the mean position. The time period of oscillation is

10.
The distance covered by a particle undergoing SHM in one time period is (amplitude = A) :

11.
The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:

12.
A spring of force constant $k$ is cut into lengths of ratio $1 : 2 : 3$. They are connected in series and the new force constant is $k'$. Then they are connected in parallel and force constant is $k"$ . Then $k' : k''$ is :

13.
A particle is executing a simple harmonic motion. Its maximum acceleration is $\alpha$ and maximum velocity is $\beta$ Then, its time period of vibration will be

14.
A body is executing simple harmonic motion with frequency ‘n’, the frequency of its potential energy is

15.
A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k''. Then k' : k'' is