NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.1 Solutions

Content Curator

NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.1 Solutions are based on concepts of Congruence of Triangles, Criteria for Congruence and theorems associated with it.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 7 Exercise 7.1 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 7 Exercise 7.1 Solutions

Exercise Solutions of Class 9 Maths Chapter 7 Triangles

Also check other Exercise Solutions of Class 9 Maths Chapter 7 Triangles

Also Check:

Important Chapter Related Topics
Mid Point Theorem	Isosceles Triangle	Congruence of triangles
Class 9 Maths Chapter 7 Triangles MCQs	Properties of inequalities and triangles	Sides of a Triangle
Similar Figures	Triangles

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
For any natural number n, \( 5^n \) ends with the digit :
- 0
- 5
- 3
- 2
View Solution
2.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution
3.
Assertion (A) : \((\sqrt{3} + \sqrt{5})\) is an irrational number.
Reason (R) : Sum of the any two irrational numbers is always irrational.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
4.
The dimensions of a window are 156 cm \(\times\) 216 cm. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.
View Solution
5.
A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))
- \(314 \sqrt{2}\) \(\text{cm}^{2}\)
- \(314\) \(\text{cm}^{2}\)
- \(\frac{3140}{3}\) \(\text{cm}^{2}\)
- \(3140 \sqrt{2}\) \(\text{cm}^{2}\)
View Solution
6.
Solve the linear equations \(3x + y = 14\) and \(y = 2\) graphically.
View Solution