NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Exercise 1.2 Solutions are based on irrational numbers.

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Check out NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.2 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 1 Number Systems

Exercise Solutions of Class 9 Maths Chapter 1 Number Systems

Also check other Exercise Solutions of Class 9 Maths Chapter 1 Number Systems

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Chapter Related Topics
Rationalize the denominator	Irrational Numbers	Addition And Subtraction Of Integers?
Relation between hcf and lcm?	Decimal expansion of rational numbers?	Integers As Exponents?
Multiplication And Division Of Integers?	Operations on Rational Numbers?	Number System

Also check:

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Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
2.
The dimensions of a window are 156 cm \(\times\) 216 cm. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.
View Solution
3.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.
View Solution
4.
An ice-cream cone of radius \(r\) and height \(h\) is completely filled by two spherical scoops of ice-cream. If radius of each spherical scoop is \(\frac{r}{2}\), then \(h : 2r\) equals
- \(1 : 8\)
- \(1 : 2\)
- \(1 : 1\)
- \(2 : 1\)
View Solution
5.
For any natural number n, \( 5^n \) ends with the digit :
- 0
- 5
- 3
- 2
View Solution
6.
Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)
View Solution

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